Question

我有一个UILabel我要在其中显示Unicode字符。以下作品：

label.text = @"\U000025A0";

现在我想从十进制数中动态生成Unicode字符，如下所示：

label.text = NSString stringWithFormat:@"\U%08x",9632];

Xcode编译器因以下错误而失败：

\U used with no following hex digits

有没有办法将十进制数9632转换为Unicode，然后将其显示在UILabel？

Answer 1

我有同样的问题来显示entypo Font特殊字符，所以我实现了我自己的EntypoStringCreator类（在SO的帮助下）。以下是将unicode号转换为nsstring的方法：

·H

@interface EntypoStringCreator : NSObject

+(NSString *)stringForIcon:(UTF32Char)char32;

@end

的.m

@implementation EntypoStringCreator


+(NSString *)stringForIcon:(UTF32Char)char32
{
    if ((char32 & 0xFFFF0000) != 0)
        return [self stringFromUTF32Char:char32];
    else
        return [self stringFromUTF16Char:(UTF16Char)(char32&0xFFFF)];
}

+(NSString *)stringFromUTF32Char:(UTF32Char)char32
{
    char32 -= 0x10000;
    unichar highSurrogate = (unichar)(char32 >> 10); // leave the top 10 bits
    highSurrogate += 0xD800;
    unichar lowSurrogate = char32 & 0x3FF; // leave the low 10 bits
    lowSurrogate += 0xDC00;
    return [NSString stringWithCharacters:(unichar[]){highSurrogate, lowSurrogate} length:2];
}

+(NSString *)stringFromUTF16Char:(UTF16Char)char16
{
    return [NSString stringWithCharacters:(unichar[]){char16} length:1];
}


@end

Answer 2

试试这个::

NSString *myString = [NSString stringWithUTF8String:"0xF09F948A"]; <-- UTF-8 Hexadecimal Encoding

myLabel.text = myString;

ios - 动态创建和显示unicode字符串

2 个答案: