Question

我正在使用jaxb将xml响应转换为java对象，我已经尝试过，但是对于嵌套的类对象，我得到了null。

XML字符串

<person>
    <name>name</name>
    <age>12</age>
    <address>
        <info>
            <contactadress>
                <city>
                </city>
                <phone>
                </phone>
            </contactadress>
        </info>
    </address>
</person>

映射java类

@XmlRootElement(name = "person")
public class person
{
    @XmlElement(name = "name")
    String name;

    @XmlElement(name = "age")
    int age:

    @XmlElement(name = "address/info/contactadress")
    person.Address address;

    @XmlRootElement(name = "contactadress")
    public static class Address{

        @XmlElement(name = "city")
        String city;

        @XmlElement(name = " phone")
        String phone;
    }
}

JaxB代码：

public Person parseXml(String xmlResponse, Person pserson)
{

 StringReader stringReader = new StringReader(xmlResponse);
            JAXBContext jaxbContext = JAXBContext.newInstance(pserson.class);
            XMLInputFactory xif = XMLInputFactory.newInstance();
            XMLStreamReader xsr = xif.createXMLStreamReader(stringReader);
            Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
            return unmarshaller.unmarshal(xsr);
}

转换后，

获取地址对象为空。

Answer 1

你的Person类看起来应该是这样的

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
"name",
"age",
"address"
})
@XmlRootElement(name = "person")
public class Person {

@XmlElement(required = true)
@XmlJavaTypeAdapter(CollapsedStringAdapter.class)
@XmlSchemaType(name = "NCName")
protected String name;
@XmlElement(required = true)
protected BigInteger age;
@XmlElement(required = true)
protected Address address;

/**
 * Gets the value of the name property.
 * 
 * @return
 *     possible object is
 *     {@link String }
 *     
 */
public String getName() {
    return name;
}

/**
 * Sets the value of the name property.
 * 
 * @param value
 *     allowed object is
 *     {@link String }
 *     
 */
public void setName(String value) {
    this.name = value;
}

/**
 * Gets the value of the age property.
 * 
 * @return
 *     possible object is
 *     {@link BigInteger }
 *     
 */
public BigInteger getAge() {
    return age;
}

/**
 * Sets the value of the age property.
 * 
 * @param value
 *     allowed object is
 *     {@link BigInteger }
 *     
 */
public void setAge(BigInteger value) {
    this.age = value;
}

/**
 * Gets the value of the address property.
 * 
 * @return
 *     possible object is
 *     {@link Address }
 *     
 */
public Address getAddress() {
    return address;
}

/**
 * Sets the value of the address property.
 * 
 * @param value
 *     allowed object is
 *     {@link Address }
 *     
 */
public void setAddress(Address value) {
    this.address = value;
}

}

Answer 2

@XmlElement注释不允许您像在问题中一样指定路径作为元素名称。相反，您需要每个嵌套级别的类。如果您愿意，可以通过XmlAdapter来使用这些课程（请参阅：Access attribute of internal element in the most simple way）。

@XmlElement(name = "address/info/contactadress")
person.Address address;

在EclipseLink JAXB (MOXy)中，我们提供@XmlPath扩展程序，您可以执行此操作：

@XmlPath("address/info/contactadress")
person.Address address;

我在博客上写了更多关于此用例的内容：

http://blog.bdoughan.com/2010/07/xpath-based-mapping.html

如何使用JAXB将xml字符串解组为对象

2 个答案: