Id uid pid weekNo year
1 1 1 28 2014
2 1 2 28 2014
3 1 3 29 2014
4 1 4 28 2015
5 1 5 28 2015
//输出应该是这样,即将weekno和year视为不同
Id uid pid weekNo year
1 1 1 28 2014
3 1 3 29 2014
4 1 4 28 2015
答案 0 :(得分:1)
如果你不关心id的值,uid,pid应该来自同一行而不是使用下面的查询来返回不同的年份和周年组
SELECT MIN(Id),MIN(uid),MIN(pid),weekno,year
FROM tableName
GROUP BY weekno,year
答案 1 :(得分:1)
如果您想保证所有值都来自相同的行,那么您需要一个查询,例如:
select t.*
from table t
where not exists (select 1
from table t2
where t2.weekno = t.weekno and t2.year = t.year and t2.pid > t.pid
);
答案 2 :(得分:-1)
从tableName GROUP BY weekno,year;
中选择*