我有一个vb.net应用程序,我应该在Restful Web服务上处理超时。 在Web.config配置文件中,我设置了属性“receiveTimeout”和“sendTimeout”,但我无法理解的是如果发生超时,如何在Web服务端执行某些操作。 基本上,如果我有超时,我应该在数据库上执行控制操作,总是在Web服务端。 我该怎么办? 这是将数据发送到Web服务的代码:
Private Function SendActivityToWEBSERVICE_POST(ByVal xmlFile As String) As Boolean
Try
sUri = "http://localhost:35299/WS/SincronizzaAttivita"
Dim encoding As ASCIIEncoding = New ASCIIEncoding()
Dim data() As Byte = encoding.GetBytes(xmlFile)
Dim webrequest As HttpWebRequest = Net.WebRequest.Create(sUri)
webrequest.Method = "POST"
webrequest.ContentType = "text/xml"
webrequest.ContentLength = data.Length
Dim newStream As Stream = webrequest.GetRequestStream()
newStream.Write(data, 0, data.Length)
newStream.Close()
Dim webresponse As HttpWebResponse = webrequest.GetResponse()
Dim stIn As IO.StreamReader = New IO.StreamReader(webresponse.GetResponseStream())
Dim strResponse As String = stIn.ReadToEnd
Dim xmlDoc As XDocument = New XDocument()
xmlDoc = XDocument.Parse(strResponse)
Return xmlDoc.Root.Value
Catch ex As Exception
Console.WriteLine("Eccezione " + ex.Message)
WriteToErrorLog(ex.Message, Environment.StackTrace, "Error")
Return False
End Try
End Function
使用此功能,我向Web服务发送大文件。我希望在发送数据失败的情况下处理Web服务端的超时,例如在网络连接出现问题的情况下。
这是界面:
<OperationContract>
<WebInvoke(Method:="POST",
RequestFormat:=WebMessageFormat.Xml,
ResponseFormat:=WebMessageFormat.Xml,
BodyStyle:=WebMessageBodyStyle.Bare,
UriTemplate:="SincronizzaAttivita")>
Function SaveDataPost(sXMLFile As Stream) As Boolean
答案 0 :(得分:0)
您可以在webrequest上添加超时属性,如下所示:
webrequest.Timeout = 200000
它会抛出超时错误,你可以抓住它。
或者您可以自己构建计时器,如果它已经超时,您可以做一些事情:
Dim boolTimeOut as boolean = false
Private Function SendActivityToWEBSERVICE_POST(ByVal xmlFile As String) As Boolean
Try
Dim MyTimer As New Timer
MyTimer.Interval = 600000 'set your time-out...
AddHandler MyTimer.Elapsed, AddressOf DisplayTimeEvent ' create handler to manage the timer...
MyTimer.Start() 'start the timer...
MyTimer.AutoReset = False
sUri = "http://localhost:35299/WS/SincronizzaAttivita"
Dim encoding As ASCIIEncoding = New ASCIIEncoding()
Dim data() As Byte = encoding.GetBytes(xmlFile)
If boolTimeOut = False Then ' if it's already time out, and do something....
Dim webrequest As HttpWebRequest = Net.WebRequest.Create(sUri)
webrequest.Method = "POST"
webrequest.ContentType = "text/xml"
webrequest.ContentLength = data.Length
Dim newStream As Stream = webrequest.GetRequestStream()
newStream.Write(data, 0, data.Length)
newStream.Close()
Dim webresponse As HttpWebResponse = webrequest.GetResponse()
Dim stIn As IO.StreamReader = New IO.StreamReader(webresponse.GetResponseStream())
Dim strResponse As String = stIn.ReadToEnd
Dim xmlDoc As XDocument = New XDocument()
xmlDoc = XDocument.Parse(strResponse)
Return xmlDoc.Root.Value
Else
' Do your thing when it's timeout in here...
End If
Catch ex As Exception
Console.WriteLine("Eccezione " + ex.Message)
WriteToErrorLog(ex.Message, Environment.StackTrace, "Error")
Return False
End Try
End Function
Public Sub DisplayTimeEvent(ByVal source As Object, ByVal e As ElapsedEventArgs)
boolTimeOut = True
End Sub
是的,我没有测试代码。