我的工具代码使用Google搜索API。
我的代码:
import com.google.gson.Gson;
class GoogleResults {
private ResponseData responseData;
public ResponseData getResponseData() {
return responseData;
}
public void setResponseData(ResponseData responseData) {
this.responseData = responseData;
}
public String toString() {
return "ResponseData[" + responseData + "]";
}
static class ResponseData {
private List<Result> results;
public List<Result> getResults() {
return results;
}
public void setResults(List<Result> results) {
this.results = results;
}
public String toString() {
return "Results[" + results + "]";
}
}
static class Result {
private String url;
public String getUrl() {
return url;
}
public void setUrl(String url) {
this.url = url;
}
public String toString() {
return "Result[url:" + url + " ]";
}
}
}
public class CrawData {
public static void main(String[] args) throws IOException, InterruptedException {
String query;
int n;
int k=0;
String site;
String resultset;
Scanner st = new Scanner(System.in);
System.out.print(" Input key search: ");
query = st.nextLine();
System.out.print("Input site: ");
site = st.nextLine();
System.out.print("Input number of result: ");
n = st.nextInt();
resultset = query + " site:" + site;
for (int j = 0; j < n; j = j + 1) {
Thread.sleep(4000);
String address = "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&start="+j+"&q=";
String charset = "UTF-8";
URL url = new URL(address + URLEncoder.encode(resultset, charset));
Reader reader = new InputStreamReader(url.openStream(), charset);
GoogleResults results = new Gson().fromJson(reader,
GoogleResults.class);
int total = results.getResponseData().getResults().size();
// Show title and URL of each results
for (int i = 0; i <= total - 1; i++) {
String Url = results.getResponseData().getResults().get(i)
.getUrl();
k = k+1;
System.out.println("URL: " +Url+ " " + k);
}
}
}
}
当我运行它时,我遇到了代码返回结果的问题。
我的网站系统返回列表网址..但不稳定。
一些图片:
有错误:线程中出现异常&#34; main&#34;显示java.lang.NullPointerException 在CrawData.main(CrawData.java:107)
帮帮我......
抱歉,我的英语太差了...... :(
答案 0 :(得分:0)
我的猜测是在这一行:
String Url = results.getResponseData().getResults().get(i)
.getUrl();
get(i)返回null或getUrl()返回null。您应该添加一些错误处理逻辑:
if (results.getResponseData().getResults().get(i) != null &&
results.getResponseData().getResults().get(i).getUrl() !=null) {
String Url = results.getResponseData().getResults().get(i)
.getUrl();
k = k+1;
System.out.println("URL: " +Url+ " " + k);
} else {
// Print some type of error here. Try to figure out why the result or the
// url is null
}