我得到的错误是“StrictMode $ AndroidBlockGuardPolicy.onNetwork”使用
我在这里尝试做的是使用jsonobject将所有这些数据发布到服务器。我真的不知道该怎么做,因为我正在使用一个活动和这个类来管理所有的http请求。
这是我的代码:
import android.util.Log;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONObject;
import java.io.IOException;
public class HttpRequestManager {
String TAG = "Request Manager";
public String RegisterUser (String deviceId, String userNames, String userSurnames, String password,
String retypedPassword, String userIds,
String userCellphone, String userEmail) {
//Log.i(TAG, deviceId);
JSONObject registerFormObject = new JSONObject();
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("http://192.168.1.110:8000/api/v1/registration");
try {
try {
registerFormObject.put("device_id", deviceId);
registerFormObject.put("device_type", "a");
registerFormObject.put("names", userNames);
registerFormObject.put("surnames", userSurnames);
registerFormObject.put("cell", userCellphone);
registerFormObject.put("email", userEmail);
registerFormObject.put("password1", password);
registerFormObject.put("password2", retypedPassword);
registerFormObject.put("identification", userIds);
}catch (Exception e){
}
httpPost.setEntity(new StringEntity(registerFormObject.toString()));
//httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
HttpResponse response = httpClient.execute(httpPost);
Log.i(TAG, response.toString());
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
Log.i(TAG, e.toString());
} catch (IOException e) {
// TODO Auto-generated catch block
Log.i(TAG, e.toString());
}
return userSurnames;
}
}
有关如何解决此错误的任何想法?
uses-permission android:name =“android.permission.INTERNET”btw。
答案 0 :(得分:1)
@Machinarius所说的是正确的。您无法在主线程上执行网络活动。但是,为了回答你的问题,我有适合你的解决方案。
你可以创建一个新的类......你可以随意调用它(为了这个例子的目的,我们假设它将是 RegUser )并且在那个类里面......把这个代码放进去。当然,更改参数寄存器功能将为您带来。
public void Register(
// Parameters it takes IN
String deviceId,
String userNames,
String userSurnames,
String password,
String retypedPassword,
String userIds,
String userCellphone,
String userEmail
)
{
//Start of the Code in Function
//Create a JSON variable of type JSON
JSONObject JSON = new JSONObject();
//Get UnixTimeStamp (Used to get UniquePushMessageID)
long unixTime = System.currentTimeMillis() / 1000L;
//Wrap all contacts and variabels to a single JSON object
try {
JSON.put("deviceId", deviceId);
JSON.put("userNames", userNames);
JSON.put("userSurnames", userSurnames);
JSON.put("password", password);
...please add more yourself.
JSON.put("contact", JSONcontacts); // Put JSON into JSON to create Array of Contacts
JSON.put("channel", channel);
JSON.put("unique", channel + String.valueOf(unixTime) ); //Create Unique MessageID (RSU-MAC+TimeInSec)
JSON.put("icon", icon);
} catch (JSONException e) {
e.printStackTrace();
}
Log.v("MAD", "About to send" + JSON.toString());
//Send this JSON object to a server
SendToServer(JSON.toString());
}
现在,在同一个类中,请创建一个名为 SendToServer 的方法。如您所见,它使用异步任务:)
@SuppressWarnings({ "unchecked", "rawtypes" })
public void SendToServer(final String JSON) {
new AsyncTask() {
@SuppressWarnings("unused")
protected void onPostExecute(String msg) {
//Not Needed
}
protected Object doInBackground(Object... params) {
//Create Array of Post Variabels
ArrayList<NameValuePair> postVars = new ArrayList<NameValuePair>();
//Add a 1st Post Value called JSON with String value of JSON inside
//This is first and last post value sent because server side will decode the JSON and get other vars from it.
postVars.add(new BasicNameValuePair("JSON", String.valueOf(JSON)));
//Declare and Initialize Http Clients and Http Posts
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(YOUR_URL);
//Format it to be sent
try {
httppost.setEntity(new UrlEncodedFormEntity(postVars));
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
/* Send request and Get the Response Back */
try {
HttpResponse response = httpclient.execute(httppost);
String responseBody = EntityUtils.toString(response.getEntity());
//Log.v("MAD", "RESPONSE: " + responseBody + " | Length: " + String.valueOf(responseBody.length()));
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
}.execute(null, null, null);
}// END of Send to Server
就是这样。现在,在您的MainActivity中,您只需要声明RegUser:
RegUser registerUser = new RegUser();
在您输入数据的所有TextField之后......只需一个简单的调用:
registerUser.Register(username, password.. etc);
我希望这能解决你的问题,对我有用。
答案 1 :(得分:0)
在Android
应用程序中,您应该避免在用户界面thread
上执行长时间运行的操作。这包括文件和网络访问。
StrictMode
允许在您的应用程序中设置策略,以避免做错误的事情。截至Android 3.0 (Honeycomb)
StrictMode 配置为在NetworkOnMainThreadException
异常时崩溃,如果在用户界面线程中访问了网络。
虽然您应该在后台线程中进行网络访问,但本教程将避免这种情况,以允许用户独立于后台处理学习网络访问。
如果您定位Android 3.0
或更高,则可以在活动的onCreate()方法开头通过以下代码关闭此检查。
在此处查看更多内容:http://www.vogella.com/tutorials/AndroidNetworking/article.html
约AsyncTask
此处http://www.vogella.com/tutorials/AndroidBackgroundProcessing/article.html
public class RequesTask extends AsyncTask<Void, Void, String>{
@Override
protected String doInBackground(Void... params) {
// TODO Auto-generated method stub
HttpRequestManager mHttpRequestManager new HttpRequestManager();
String returnValue = mHttpRequestManager.RegisterUser()
return returnValue;
}
@Override
protected void onPostExecute(String result) {
// TODO Auto-generated method stub
super.onPostExecute(result);
//your result here
}
}