Question

我试图提取与一个或多个保管人有关系的机构名称。

例如，让我们说机构A与保管人1,2和3有关系然后我希望结果只显示机构A，而不是机构B和C.基本上我只想看到拥有托管人1,2,3的机构，而不是仅与托管人1或2或3有关系的机构。

（希望这个问题有点意义）

以下是我正在处理的SQL：

select i.institution_name, custodian_name
from institution i
join institution_has_custodian ihcu
on i.institution_id = ihcu.institution_id
join custodian c
on c.custodian_id = ihcu.custodian_id
where c.custodian_name in ('JPMorgan (00902/82D)','BNY Mellon (Formerly Bony) (00901/93I)')

Answer 1

您可以使用外部查询并按institution_name分组，如下所示

select institution_name, count(custodian_name) as cust_count
from
(
select i.institution_name, custodian_name
from institution i
join institution_has_custodian ihcu
on i.institution_id = ihcu.institution_id
join custodian c
on c.custodian_id = ihcu.custodian_id
where c.custodian_name in ('JPMorgan (00902/82D)',
'BNY Mellon (Formerly Bony) (00901/93I)')
) tab
group by institution_name
having cust_count = 3

MySQL Workbench - 如何从多个where子句获得结果？

1 个答案: