Question

我有Android＆lt; - ＆gt; Arduino蓝牙通信。有时Android会从Arduino获取两条消息，而不是一条消息。我的意思是：如果我发送给前任。 5字节消息＆＃34; 1234＆＃34;从Arduino到Android通过蓝牙，有时我会得到＆＃34; 1＆＃34;一条消息中有1个字节，第二条消息中有＆＃34; 234＆＃34; + \ n 4个字节。有时我会得到满满的＆＃34; 1234＆＃34; + \ n 5字节消息，并且没有任何线索的原因。我需要通过分隔符拆分输入消息，如果我收到单独的消息，我会崩溃。所以我需要将字节追加到字符串直到新行char来。

如何将字符串添加到字符串直到＆＃34; \ n＆＃34;新行char来了吗？

数据出现的情况：

    case BLUETOOTH_RECEIVED:
        byte[] buffer = (byte[])msg.obj;
        int len = msg.arg1;
        if (len > 0 && buffer != null) {
            onBluetoothRead(buffer, len);
        }
        break;
    }

缓冲区到字符串：

private void onBluetoothRead(byte[] buffer, int len) {
    Log.i(LOGGER_TAG, String.format("Received: " +  output.replace("\n", "") + " message of " + "%d bytes", len));
    String output = new String(buffer, 0, len); // Add read buffer to new string
    m_deviceOutput.append(output); // Add (not replace) string to TextView
    StringTokenizer  splitStr = new StringTokenizer(output, ","); // split string by comma
    String numberOne = splitStr.nextToken(); // First split string
    String numberTwo = splitStr.nextToken(); // Second split string
    numberOne = numberOne.replaceAll("\\D+",""); // replace all chars, leave only numbers
    numberTwo = numberTwo.replaceAll("\\D+","");
}

logcat的：

07-22 14:06:15.099: I/DeviceActivity(20370): Received: 1234 message of 5 bytes
07-22 14:06:20.599: I/DeviceActivity(20370): Received: 1234 message of 5 bytes
07-22 14:06:27.349: I/DeviceActivity(20370): Received: 1 message of 1 bytes
07-22 14:06:27.469: I/DeviceActivity(20370): Received: 234 message of 4 bytes
07-22 14:06:37.219: I/DeviceActivity(20370): Received: 1 message of 1 bytes
07-22 14:06:37.349: I/DeviceActivity(20370): Received: 234 message of 4 bytes

在Arduino我可以这样写，我想要类似的东西：

//Get data from RS485:
void READ01(){
  while (mySerial.available()){
    mySerial.read();
  }
    mySerial.println("01READ");
    momentas1="";
    delay(20);

    while (mySerial.available()) { 
      char c = mySerial.read();
      if (c == '\n'){
     break;
      }
      momentas1 += c; 
      }
}

此void READ01将字符串添加到字符串，直到新行字符来。

Answer 1

您可以使用类似缓冲区的实现，方法是将获取的字符串添加到另一个字符串，直到收到“\ n”。

private String packet = "";
private void onBluetoothRead(byte[] buffer, int len) {
    Log.i(LOGGER_TAG, String.format("Received: " +  output.replace("\n", "") + " message of " + "%d bytes", len));
    String output = new String(buffer, 0, len); // Add read buffer to new string
    packet += output;
    if (packet.endsWith( "\n" ) {
        //do what you need to do
        m_deviceOutput.append(output); // Add (not replace) string to TextView
        StringTokenizer  splitStr = new StringTokenizer(packet, ","); // split string by comma
        String numberOne = splitStr.nextToken(); // First split string
        String numberTwo = splitStr.nextToken(); // Second split string
        numberOne = numberOne.replaceAll("\\D+",""); // replace all chars, leave only numbers
        numberTwo = numberTwo.replaceAll("\\D+","");
        packet = "";
    }

}

字节数组到字符串直到'\ n'

1 个答案: