我有这个输入字符串(包含换行符):
That is
a test.
seems to work pretty good? working. Another test again.
我希望达到这种状态:
That is a test.
seems to work pretty good? working. Another test again.
有什么想法吗?
我正在尝试这个:
replaceAll("[^\\.]\\n", "");
答案 0 :(得分:0)
您可以使用lookbehind(请参阅documentation)。这将查看是否存在非点字符而未实际替换该字符(从而删除最后一个字的一部分)。此外,您应该用空格替换换行符,以便不加入单词。
text.replaceAll("(?<=[^\\.])\\n", " ")
或者,您可以捕获组中的非点字符并将其重新插入替换中:
text.replaceAll("([^\\.])\\n", "$1 ")
两者都会给你
That is a test.
seems to work pretty good? working. Another test again.