Question

我有一个表App与应用程序（AppID, RequestDt, OrgID），一个表Branch，其名称为分支（branch_id, branch_name）和Wspace与员工（{ {1}}）

branchID, NmbrEmp

此选择将返回:(我只显示两行的例子，实际上有超过1000行）

select  
    substring(b.RequestDt,1,6) as Date,
    a.branch_name,
    d.NmbrEmp,
    COUNT(b.AppId) as TotalApp,
    SUM(convert(int,b.OKFlg)) as TotalAppOK
    SUM(convert(int,b.NotOKFlg)) as TotalAppNOK, 
from    
    App b 
join 
    Branch a on a.branch_id  = b.OrgId 
left join 
    WSpace d on a.branch_id = d.branchID 
where 
    substring(b.RequestDt,1,6) >= 201301
group by 
    substring(b.RequestDt,1,6), a.branch_name, d.NmbrEmp

现在我想添加Date Branch NmbrEmp TotalApp TotalAppOK TotalAppNOK -------------------------------------------------------------------- 201402 Home 5 28 20 8 201402 Office 4 15 8 7 201403 Home 5 24 7 17 201403 Office 4 30 9 21的下一列。此INFO位于另一个名为INFO的表中，该表仅包含特定的应用程序（App2）

我想要从表App2中INFO为1的count行，并将该数字放入每行的下一列。

但是每次它都会让我的原始群体变得混乱......那是因为在App2中只有＆＃34; OKApps＆＃34; （加上有些应用程序根本不在应用程序中）所以当我这样做时：

AppID, INFO

我的NOTOK应用程序将从群组中消失，当我离开加入时，我之前有更多应用程序...

感谢您的帮助

Answer 1

就像我在评论中所说，您可以像变量一样使用，或者只使用CROSS JOIN添加：

DECLARE @someTable TABLE ([Date] VARCHAR(10), Branch VARCHAR(10), NmbrEmp INT, TotalApp INT, TotalAppOK INT, TotalAppNOK INT)

INSERT INTO @someTable SELECT '201402', 'Home', 5, 28, 20, 8
INSERT INTO @someTable SELECT '201402', 'Office', 4, 15, 8, 7
INSERT INTO @someTable SELECT '201403', 'Home', 5, 24, 7, 17
INSERT INTO @someTable SELECT '201403', 'Office', 4, 30, 9, 21



DECLARE @App2 TABLE (AppID INT, INFO INT)

INSERT INTO @App2 SELECT 2, 2
INSERT INTO @App2 SELECT 3, 1
INSERT INTO @App2 SELECT 4, 2

---FIRST CHOICE

DECLARE @App2Count INT = (SELECT COUNT(*) FROM @App2 WHERE INFO = 2)

SELECT Date, Branch, NmbrEmp, TotalApp, TotalAppOK, TotalAppNOK, @App2Count as App2
FROM @someTable

---SECOND CHOICE
SELECT Date, Branch, NmbrEmp, TotalApp, TotalAppOK, TotalAppNOK, A.App2 as App2
FROM @someTable sT
CROSS JOIN (SELECT COUNT(*) as App2 FROM @App2 WHERE INFO = 2) as A

Answer 2

您应该只计算子查询中的Info并加入：

select  substring(b.RequestDt,1,6) as Date,
    a.branch_name,
    d.NmbrEmp,
    COUNT(b.AppId) as TotalApp,
    SUM(convert(int,b.OKFlg)) as TotalAppOK
    SUM(convert(int,b.NotOKFlg)) as TotalAppNOK, 
    e.C 
from    
    App b 
join Branch a on a.branch_id  = b.OrgId 
left join WSpace d on a.branch_id = d.branchID 
LEFT JOIN   
    (SELECT COUNT(*) AS C, AppID 
        FROM App2 
        WHERE Info = 1 
        GROUP BY AppId) e 
on e.AppId = b.AppId

where 
    substring(b.RequestDt,1,6) >= 201301
group by 
    substring(b.RequestDt,1,6), a.branch_name, d.NmbrEmp

加入具有更多连接属性的表

2 个答案: