Question

models.py

class Album(models.Model):
    file_upload = models.FileField(upload_to=content_file_name)
    name_content = models.CharField(max_length=100)

功能就在这里

def content_file_name(instance, filename):
    upload_dir = os.path.join('uploads', 'resource')
    return os.path.join(upload_dir, filename)

forms.py

class Albumform(forms.Form):
    name_content = forms.CharField(max_length=100)
    file_upload = forms.FileField( 'please select' )

这是我的views.py

from django.forms.formsets import formset_factory
def viewalbum(request):    
    AlbumFormSet = formset_factory(Albumform, extra=3, max_num=10,)
    if request.method == 'POST':
        formset = AlbumFormSet(request.POST, request.FILES)
        if formset.is_valid():
            albumvalue = Album()
            albumvalue.name_content = request.POST.get('name_content', None)
            albumvalue.file_upload = request.FILES['file_upload']
            albumvalue.save()


            return HttpResponseRedirect(reverse('views.viewalbum'))
    else:
        formset = AlbumFormSet()
    return render_to_response('audio/test.html',{'formset': formset}, context_instance=RequestContext(request))

，html看起来像这样

<form action="" method="POST" enctype="multipart/form-data">
    {{ formset.management_form }}
    {% csrf_token %}
    <table>
        {% for form in formset.forms %}
            {{ form }}
        {% endfor %}
    </table>

问题是我当时只能上传一个文件。给我解决方案，同时上传多个文件并保存到资源文件夹中。感谢

Answer 1

如果要上传多个文件，则需要多个文件字段。这是您的选择A.如果您选择使用它，请创建formset并使用它来提供多个文件上传。

您的选项B是使用某种可以上传多个文件的javascript小部件。

使用formset上传多个文件？

1 个答案: