我从JSON获取数据。喜欢这个
-(void)connectionDidFinishLoading:(NSURLConnection *)connection
{
al=[NSJSONSerialization JSONObjectWithData:webData options:0 error:nil];
NSLog(@"String String %@",al);
for (array in al) {
NSLog(@"array is array %@",array);
}
}
PickerView方法: -
- (NSInteger)numberOfComponentsInPickerView:
(UIPickerView *)pickerView
{
return 1;
}
- (NSInteger)pickerView:(UIPickerView *)pickerView
numberOfRowsInComponent:(NSInteger)component
{
return array.count;
}
- (NSString *)pickerView:(UIPickerView *)pickerView
titleForRow:(NSInteger)row
forComponent:(NSInteger)component
{
return array[row];
}
我试过这样但是它显示空的PickerView.So请给我任何想法。
感谢高级。 我的Json喜欢这样: -
[[1,"Hyd"],[2,"viz"]]
请告诉我有关我的问题的任何想法。
答案 0 :(得分:0)
这样的事情应该有效:
- (NSInteger)numberOfComponentsInPickerView:
(UIPickerView *)pickerView
{
return [((NSArray *)array[0]) count]; // check for boundary conditions
}
- (NSInteger)pickerView:(UIPickerView *)pickerView
numberOfRowsInComponent:(NSInteger)component
{
return array.count;
}
- (NSString *)pickerView:(UIPickerView *)pickerView
titleForRow:(NSInteger)row
forComponent:(NSInteger)component
{
return array[row][1]; // title exists at 1 index of each 2d array.
}