如何使用php中的复选框删除记录?

时间:2014-07-22 04:24:17

标签: php mysql

需要删除记录,这是我的代码:

<input type="submit" name="delete" value="delete"/>  
<?php
    if(isset($_POST['delete'])) 
    {  
        $cnt=array(); 
        $cnt=count($_POST['chkbox']);  
        for($i=0;$i<$cnt;$i++)   
        {
            $del_id=$_POST['chkbox'][$i];
            $query="DELETE FROM menu_detail WHERE vt_id=".$del_id;
            mysql_query($query);   
        } 
    } 
?>  
// I draw checkboxes using this where as I m fetching data from table...
<?php  
   $col = "row0"; $i = 0; $a=1;
   while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
   if ($i == 0)  { $col = "row0"; $i = 1; } else { $col = ""; $i = 0; }
?>
<tr class="<?php echo $col; ?>">
<td>
    <input type="checkbox" name="chkbox" value="checkbox[<?php echo $row['vt_id']?>]" />
</td>

看图像会让你知道我被困的地方

enter image description here

1 个答案:

答案 0 :(得分:0)

看看

       $tableRow = array("id","name","code"): // assume It must from Database

         <form action="your_action.php"  method="post" id="bulkDel" >

       <table>
               <thead>
                      <th><input type="checkbox" id="checkAll" /></th>
                      <th>....</th> <!--and so on-->
              </thead>
           <?php
                 foreach($tableRow as $row){
                       ?>
                     <tr>
                           <td> <input tyep="checkbox"  name="check[]" /></td>
                           <td>.....</td> <!-- and so on --> 
                     </tr>

                  <?php

                 }
            ?>

      </table>
      <a href="javascript:void(0);"id="bulkDeleteBut" >Delete selected</a>
   </form>

  // jquery check all checkboxes

  $(document).on('click','#checkAll',function(){
                    $('input[name="check[]"]').prop('checked',$(this).is(":checked"));
  });


 $(document).on('click','#bulkDeleteBut',function(){
             var len = $('input[name="check[]"]')..serializeArray().length;
             if(len>0){
                     $('#bulkDel').submit();
             }else{
              alert("Check atleast one record");
            } 
 });


 // server side php
   if(isset($_POST['check'])){
       $ar = $_POST['check'];
        foreach($ar as $primary_key){
             // perform mysql delete query and return back to table page
        }
   }