Question

我正在尝试搜索我拥有的员工姓名的文本文件，但它似乎没有工作，但它也没有丢失任何错误。每当我在这个文件中搜索一个单词时，它都会进入get_the_info函数，但它似乎永远不会到达for循环。我假设这是因为我使用了print语句试图找出问题所在。我是编程新手，但我认为这是解决一些问题的常见惯例？无论如何，代码是：

import os
import sys

class find_employee:

    def __init__(self):
        self.get_the_info()

    def get_the_info(self):

        print "inside get info funct"
        self.naples_empschedule = open("schedule.txt","r+")
        self.read_schedule = self.naples_empschedule.readlines()
        self.name = raw_input("  Enter your first and last name please  ")
        for line in self.naples_empschedule:
            print " now inside for loop"
            self.values = aline.split()
            if self.name in line:
                print ("Name:", self.values[0,1],"\n", "Position:", self.values[3],"\n", "Total Hours:", self.values[11]) 
            else:
                print ("You dont work here")


find_employee()

Answer 1

self.values[0,1]

在这里，您尝试使用引发错误的元组（0,1）索引列表。而是使用

self.values[0]

或

self.values[1]

取决于您希望从列表中选择哪个项目。

Answer 2

你正在混合类和功能。试试这个：

class EmployeeFinder(object):
    def __init__(self, path_to_schedule, name=None):
        self.name = name or raw_input("Enter your first and last name please: ")
        self.path_to_schedule = path_to_schedule
    def get_the_info(self):
        with open(path_to_schedule, "r") as schedule_file:
            for line in schedule_file:
                values = line.split()
                if self.name in line:
                    print("Name: " + values[0:1] + "\n" + \
                          "Position: " + self.values[3] + "\n" \
                          "Total Hours: ", self.values[11])
                    # note that this still won't work because values[0:1]
                    # will return a list, not a string. You might need
                    # ' '.join(values[0:1]).
                else:
                    print("You don't work here")

employeefinder = EmployeeFinder("path/to/schedule/file", "Adam Smith")
employeefinder.get_the_info()

然而，看起来你可能会更好地使用一个函数，而不是试图强制对象。函数式编程并不是一件坏事。

def find_employee(path_to_schedule, name):
    with open(path_to_schedule, "r") as schedule_file:
        for line in schedule_file:
            if name in line:
                values = line.split()
                new_name = ' '.join(values[0:1]) # I'm guessing at your intent
                position = values[3]
                hours = values[11]
                print("Name: {}\nPosition: {}\nTotal Hours: {}".format(
                    new_name, position, hours))

（我的上一个例子使用string formatting，这是一个比字符串连接更好的解决方案）

Answer 3

我认为你的for line in self.naples_empschedule:

应为for line in self.read_schedule:。

在文本文件中搜索不起作用的单词并且不会抛出任何错误

3 个答案: