表示带有两个无符号16位整数的无符号32位值

Question

如何在Swift中使用两个UInt32数字表示UInt16，反之亦然？

例如，UInt32 65536应该是（UInt16）1和（UInt16）65535，而（UInt16）0和（UInt16）65533组合到（UInt32）65533

Answer 1

简单的按位操作

var number1: UInt16 = 1
var number2: UInt16 = 65535
let number: UInt32 = UInt32(number1) << 16 | UInt32(number2) 

number1 = UInt16(number >> 16)
number2 = UInt16(number & 0xFFFF)

Answer 2

func toInt16(value:UInt32)->(UInt16,UInt16){
    return (UInt16(value >> 16),UInt16(value & UInt32(UInt16.max)))
}

func toInt32(value1:UInt16,value2:UInt16)->UInt32{
    return (UInt32(value1) << 16 | UInt32(value2))
}