我有一个RESTFUL API服务,它返回具有唯一ID号的位置的City,State,Zip等。在我获取数据的函数中,我返回一个名为“List”的数组。例如,数组导致<string>Kansas City</string>
。
我如何拥有<City>Kansas City</City> <State>MO</State>.
等客户代码?
我在函数中的代码片段是:
string [] List = new string [7];
List[0]= City;
List[1]= County;
List[2]= State;
List[3]=Postal;
List[4]=isDefaultLocation;
List[5]=locationId;
List[6]=AtlasKey;
return List;
使用example.com/locations/id/10000
以XML格式返回结果答案 0 :(得分:0)
您必须创建自己的类,例如:
using System.Xml.Serialization; // XML serialization requires this namespace
using System.IO;
[XmlRootAttribute("Info")]
public class Info
{
// static constructor will create serializer instance
static Info()
{
Serializer = new XmlSerializer(typeof(Info));
}
// here write constructor based on array of strings
// this method will serialize current object to stream
public void SerializeToXml(Stream stream)
{
Serializer.Serialize(stream, this);
}
// this static method will deserialize object from stream
public static Info DeserializeFromXml(Stream stream)
{
return Serializer.Deserialize(stream) as Info;
}
[XmlElement("City")] // use XmlElement, not XmlAttribute
public string City
{
get;
set;
}
// here you can add your other fields like above
[XmlIgnore] // we want to be sure that this field won't be serialized
private static XmlSerializer Serializer
{
get;
set;
}
}