我想获取一份工作列表(称为resultStream)并计算完全完成的工作百分比。
public class Job {
private Date date;
private String success;
// Getter and setter and constructor.
}
该列表包含以下内容:
new Job("TODAY", "YES");
new Job("TODAY", "YES");
new Job("YESTERDAY", "YES");
new Job("TODAY", "NO");
这是我到目前为止的代码:
resultStream.stream().parallel().filter(result -> {
if ("YES".contains(result.getSuccess())) {
return true;
} else {
return false;
}
}).collect(groupingBy(Job::getDate, HashMap::new, counting()));
这将返回一个HashMap(Date,Long),其中包含以下内容:
今天,2
昨天,1
我实际上想要以下结果:
今天,66%
昨天,100%
提前致谢。
答案 0 :(得分:7)
平均为双倍可以这样做:
public static void main(final String... args) {
final List<Job> jobs = new ArrayList<>();
jobs.add(new Job(LocalDate.now(), "YES"));
jobs.add(new Job(LocalDate.now(), "NO"));
jobs.add(new Job(LocalDate.now(), "YES"));
jobs.add(new Job(LocalDate.now()
.minusDays(1), "YES"));
final Map<LocalDate, Double> result = jobs.stream()
.collect(
Collectors.groupingBy(Job::getDate,
Collectors.mapping(Job::getSuccess, Collectors.averagingDouble(success -> {
return "YES".equals(success) ? 1 : 0;
}))));
// result = {2014-07-20=1.0, 2014-07-21=0.6666666666666666}
System.out.println(result);
}
作为字符串:
public static void main(final String... args) {
final List<Job> jobs = new ArrayList<>();
jobs.add(new Job(LocalDate.now(), "YES"));
jobs.add(new Job(LocalDate.now(), "NO"));
jobs.add(new Job(LocalDate.now(), "YES"));
jobs.add(new Job(LocalDate.now()
.minusDays(1), "YES"));
final Map<LocalDate, String> result = jobs.stream()
.collect(
Collectors.groupingBy(
Job::getDate,
Collectors.collectingAndThen(
Collectors.mapping(Job::getSuccess, Collectors.averagingDouble(success -> {
return "YES".equals(success) ? 1 : 0;
})), avg -> String.format("%,.0f%%", avg * 100))));
// result = {2014-07-20=100%, 2014-07-21=67%}
System.out.println(result);
}