首先我知道这个节目有点冗长,但是如果我不发布所有节目你可能会感到困惑。基本上我需要读取大约5行文本的文件,使用strtok函数解析每一行,然后将我得到的字符串存储到二叉树中。然后,用户将搜索二叉树以查看他搜索的命令是否位于树中。现在我有一种类型的编译错误,我无法弄清楚我的生活。所以我还没有开始编译,一旦我开始编译,我肯定会有更多的错误。就像我说我知道它相当长,所以任何帮助都表示赞赏。我将发布我的代码然后给出的示例输出,然后编译错误,我无法弄清楚。非常感谢您的帮助。
#include<stdlib.h>
#include<string.h>
#include<stdio.h>
#define COMMAND_NAME_LEN 50
#define MAX_SPLIT_SIZE 50
#define MAX_BUFF_SIZE 50
typedef struct Command_ {
char name[COMMAND_NAME_LEN];
int expected_param_count;
struct Command_ *left;
struct Command_ *right;
}Command;
typedef struct StringArray_ {
char **strings;
int size;
}StringArray;
StringArray* tokenizer (char *string, const char* delimiters);
void free_string_array(StringArray *sr);
void create_commands_tree(Command **commands, const char *file);
void insert_into_commands_tree(Command** node, char** data);
Command* get_command(Command *node, const char *command);
Command* create_command(char **data);
void destroy_commands_tree(Command* node);
void display_commands(Command *node);
int main (int argc, char *argv[]) {
if (argc < 2) {
printf("%s is missing commands.dat\n", argv[0]);
return 0;
}
Command* options = NULL;
create_commands_tree(&options,argv[1]);
int checking = 1;
char input_buffer[MAX_BUFF_SIZE];
do {
printf("Command: ");
fgets(input_buffer,MAX_BUFF_SIZE,stdin);
StringArray* parsed_input = tokenizer(input_buffer," \n");
Command* c = get_command(options,parsed_input->strings[0]);
if( c && parsed_input->size == c->expected_param_count) {
if (strcmp(c->name, "quit") == 0){
checking = 0;
}
printf("Valid command used\n");
}
else {
printf("Invalid command, please try again\n");
}
free_string_array(parsed_input);
}while (checking);
destroy_commands_tree(options);
}
void create_commands_tree(Command **commands, const char *file) {
FILE *input;
input = fopen(file, "r");
char strings[256];
Command *temp;
StringArray *temp2;
while(fgets(strings,100,input) != NULL){
temp2 = tokenizer(strings, "\n");
insert_into_commands_tree(&temp,temp2->strings);
}
}
void insert_into_commands_tree(Command** node, char** data) {
Command **new_ = node;
if(node == NULL){
*new_ = create_command(data);
}
else if( new_ != NULL){
if(strcmp(data[0],(*new_)->name) < 0)
insert_into_commands_tree(&(*new_)->left,data);
else if(strcmp(data[0], (*new_)->name) > 0)
insert_into_commands_tree(&(*new_)->right,data);
}
}
Command* create_command(char **data) {
Command* new_;
new_ = (Command*)malloc(sizeof(Command));
strncpy(new_->name, data[0], COMMAND_NAME_LEN);
new_->expected_param_count = 0;
new_->right = NULL;
new_->left = NULL;
return new_;
}
Command* get_command(Command *node, const char *command) {
Command *temp = node;
int compare;
if(temp){
compare = strcmp(node->name, command);
if(compare == 0){
return temp;
}
else if(compare < 0){
return (get_command(node->right, command));
}
else{
if(compare > 0){
return (get_command(node->left, command));
}}
}
return temp;
}
void destroy_commands_tree(Command* node) {
if( node == NULL){
return;
}
destroy_commands_tree(node->left);
destroy_commands_tree(node->right);
free(node);
}
void display_commands(Command *node) {
if(node != NULL){
printf("\npickup <item>");
printf("\nhelp ");
printf("\nquit ");
printf("\nload <file>\n\n");
}
}
StringArray* tokenizer (char *string, const char* delimiters){
StringArray *temp = (StringArray*)malloc(sizeof(StringArray));;
char *split;
split = strtok(string, delimiters);
while(split != NULL)
{
split = strtok(string, delimiters);
temp->strings = &split;
}
return temp;
}
void free_string_array(StringArray *sr) {
while(sr != NULL)
free(sr);
free(sr);
}
以下是给出的示例输出:
]$ ./a.out commands.dat
Command: pickup
Invalid command, please try again
Command: pickup ball
Valid command used
Command: quit 1
Invalid command, please try again
Command: load
Invalid command, please try again
Command: load bak.sav
Valid command used
Command: help
Valid command used
Command: help 2
Invalid command, please try again
Command: quit
Valid command used
我们读到的文件如下:
pickup,2
help,1
quit,1
load,2
答案 0 :(得分:1)
Command **new_ = node;
这里变量new_
是一个指向指针的指针,你试着像这样使用ist
new_->name
访问结构的名称成员。
您需要对其进行反驳,以便Command*
使用->
运算符,这样做:
(*new_)->name;