Question

我使用以下代码将多个图像存储到数据库中每个工作正常存储和显示上传我需要的是当我一次上传3张照片为单个上传创建三行如何在多个图像中存储多个图像的路径一行

class Upload_Rename {
const ALLOWED_TYPES = "jpg,gif,png";
public static function generate_new_name($extension, $uppercase = true, $prefix = '', $sufix = '') {
$new_name = $prefix . uniqid() . '_' . time() . $sufix;
return ($uppercase ? strtoupper($new_name) : $new_name) . '.' . $extension;
}

public static function check_and_get_extension($file) {
$file_part = pathinfo($file);
$allowed_types = explode(",", Upload_Rename::ALLOWED_TYPES);
if (!in_array($file_part['extension'], $allowed_types)) {
    throw new Exception('Not ok.. bad bad file type.');
}
return $file_part['extension'];
}

public function upload($file, $target_destination) {
if (!isset($file['tmp_name'])) {
    throw new Exception('Whaaaat?');
}
$_name = $file['name'];
$_tmp = $file['tmp_name'];
$_type = $file['type'];
$_size = $file['size'];
$file_extension = '';
try {
    $file_extension = Upload_Rename::check_and_get_extension($_name);
} catch (Exception $e) {
    throw new Exception('Ops.. file extension? what? ' . $e->getMessage());
}
$new_name = Upload_Rename::generate_new_name($file_extension, true, 'whaat_', '_okey');
$destination = $target_destination . DIRECTORY_SEPARATOR . $new_name;
move_uploaded_file($_tmp, $destination);
return $destination;
}

public function multiple_files($files, $destination) {
$number_of_files = isset($files['tmp_name']) ? sizeof($files['tmp_name']) : 0;
$errors = array();
$paths=array();
for ($i = 0; $i < $number_of_files; $i++) {
    if (isset($files['tmp_name'][$i]) && !empty($files['tmp_name'][$i])) {
        try {
            $path=$this->upload(array(
                'name' => $files['name'][$i],
                'tmp_name' => $files['tmp_name'][$i],
                'size' => $files['size'][$i],
                'type' => $files['type'][$i]
                    ), $destination);
             $paths[]=$path;
        } catch (Exception $e) {
            array_push($errors, array('file' => $files['name'][$i], 'error' => $e->getMessage()));
        }
    }
}
return $paths;
}

}

if ($_FILES) {
$upload = new Upload_Rename();
$destination = 'upload';
$paths=$upload->multiple_files($_FILES['myfile'], $destination);

//Fill this with correct information
$mysql_hostname = "";
$mysql_user = "";
$mysql_password = "";
$mysql_database = "";
$tbl_name="test";
$pathfield_name='path';
//
$mysql= new mysqli($mysql_hostname,$mysql_user,$mysql_password,$mysql_database);
foreach($paths as $path){
$query='INSERT INTO `'.$tbl_name.'` (`'.$pathfield_name.'`) VALUES ("'.$mysql->escape_string($path).'");';
$mysql->query($query);}
$mysql->close();
}
?>

<form  method="post" enctype="multipart/form-data">
<?php for ($i = 0; $i < 10; $i++): ?>
file: <input type="file" name="myfile[]"><br>
<?php endfor; ?>
<input type="submit">
</form>

我使用此代码在sql中创建表

CREATE TABLE IF NOT EXISTS `test` (
`path` text(50) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

Answer 1

首先获取路径feild并存储在一个变量中然后插入

foreach($paths as $path){  $pathfield_name.=$pathfield_name."/";   }


$query='INSERT INTO `'.$tbl_name.'` (`'.$pathfield_name.'`) VALUES ("'.$mysql->escape_string($path).'");';
$mysql->query($query);

将多个图像存储在单行的SQL数据库中

1 个答案: