Question

Hello Ladies and Gents，

我在oracle SQL中为查询找到解决方案时遇到问题：

这是我需要的查询示例：

Select Result_Date as hour , Type , Count(Id) as Number From Results 
Where Result_Date Between Today'06:00' And today'14:00'
group by result_date , type

结果日期包含小时，结果日期的格式为时间戳。如何在不在两个语句之间输入日期的情况下完成此查询，仅在我今天要搜索的时间之间。

如果您有任何想法请告诉我，欢迎任何想法。

Answer 1

您可以在时间戳上使用trunc()功能，这样可以做到您想要的：

Select trunc(Result_Date, 'HH24') as hour , Type , Count(Id) as Number From Results 
Where trunc(Result_Date, 'HH24') Between '06:00' And '14:00' and
      trunc(Result_Date) = trunc(sysdate)
group by trunc(Result_Date, 'HH24'), type ;

注意：

trunc()日期默认为当天。如果您愿意，可以为此添加特定格式。

Answer 2

编辑，这对我有用

   Select to_number(extract(hour from Result_Date)) as hour , Type , Count(Id) as Number From Results Where To_Date(Trunc(Result_Date)) = To_Date(Trunc(Current_Timestamp))
        and to_number(extract(hour from Result_Date)) Between 6 and 14     
            group by  to_number(extract(hour from )Result_Date) as hour  , type

@Gordon Linoff，谢谢你对trunk的建议，它帮我分配了

Oracle日期/时间操作查询

2 个答案: