Question

如何用这样的php变量检查数据库？

我有

$check = "1234567890";

这是表：check_data

 _________ ______________________________________________________________
|   id    |                         key_pass                             |
|_________|______________________________________________________________|
|____1____|_______________1234567890abcdefghij___________________________|
|____2____|_______________6545ryu76543werfdt54___________________________|
|____3____|_______________345jfuryt75yrhtufkgo___________________________|
|____4____|_______________weoiufoiweu9ew8ew8w8___________________________|
|____5____|_______________oi34ioruiofuefiusdfo___________________________|
|____6____|_______________iuyiuysdifuysfiuyfds___________________________|

我想这样检查一下。

$sql = "SELECT * FROM check_data WHERE key_pass(first char to ten char) = '$check'";
$query = mysql_query($sql);
$result = mysql_fetch_array($query);
if($result)
  {echo "found";}
else
  {echo "not found";}

我该怎么做？

Answer 1

检查MySQL手册，您正在寻找SUBSTRING功能。

$sql = "SELECT * FROM check_data WHERE SUBSTRING(key_pass, 1, 10) = '" . mysql_real_escape_string($check) . "';

Answer 2

尝试 LEFT

LEFT(key_pass , 10);

像

$sql = "SELECT * FROM check_data WHERE LEFT(key_pass , 10) = '$check'";

您也可以使用 SUBSTRING

$sql = "SELECT * FROM check_data WHERE SUBSTRING(key_pass ,1, 10) = '$check'";

Answer 3

你需要的功能是LIKE，

$sql =  "SELECT * FROM check_data WHERE key_pass like ('$check%')";

你也可以

$sql =  "SELECT * FROM check_data WHERE SUBSTR(key_pass,1,10) = '$check%'";

Answer 4

您可以使用LEFT()这样的功能：

ql = "SELECT * FROM check_data WHERE left(key_pass,10) = '$check'";

有一整套字符串函数可能很有用。检查MySQL reference

Answer 5

$sql = "SELECT * FROM check_data WHERE SUBSTRING(key_pass, 1, 10)= '$check'";

Answer 6

$sql = "SELECT * FROM check_data WHERE key_pass LIKE  % $check %";
$query = mysql_query($sql);
$result = mysql_fetch_array($query);
if($result)
  {echo "found";}
else
  {echo "not found";}

Answer 7

试试这个

    "SELECT * FROM check_data WHERE SUBSTR(key_pass,1,10) = ".$check

或

    "SELECT * FROM check_data WHERE key_pass LIKE '".$check."%'"

如何用这样的php变量检查数据库？

7 个答案: