Question

我有以下复合形式，我想将该位置作为模型/对象传递给LocationType，我如何在buildForm内做同样的事情？

如果这是一个常规控制器，那么我会这样做：

$registrationForm = $this->createForm(new ShopRegistrationFormType(), $location, array('label' => false, 'required' => false));

但我怎样才能在FormType中执行相同的操作：

class ShopRegistrationFormType extends AbstractType
{

    private $location;

    public function __construct( $location = null)
    {
        $this->location = $location;
    }

    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('location', new LocationType())
    }

    public function setDefaultOptions(OptionsResolverInterface $resolver)
    {
        $resolver->setDefaults(array(
            'cascade_validation' => true,
        ));
    }

    public function getName()
    {
        return 'shop_registration';
    }
}

Answer 1

尝试通过＆＃39;数据＆＃39;添加模型/对象属性：

class ShopRegistrationFormType extends AbstractType
{

    private $location;

    public function __construct( $location = null)
    {
        $this->location = $location;
    }

    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('location', new LocationType(), array(
            'data' => $this->location,
        ));
    }

    public function setDefaultOptions(OptionsResolverInterface $resolver)
    {
        $resolver->setDefaults(array(
            'cascade_validation' => true,
        ));
    }

    public function getName()
    {
        return 'shop_registration';
    }
}

希望它有所帮助。

在Symfony2中将模型传递给复合形式

1 个答案: