您是否有一段代码可以手动格式化Android中的指定电话号码?我不想使用PhoneUtils。我需要这个用于我课程的项目。
答案 0 :(得分:2)
我遇到了类似的问题,请查看下面的代码:
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count)
{
String str;
/*Log.i("ED",
"LengthBefore before (lengthBefore = lengthAfter;): "
+ String.valueOf(lengthBefore));*/
lengthBefore = lengthAfter;
lengthAfter = s.length();
/*Log.i("ED",
"LengthBefore after (lengthBefore = lengthAfter;): "
+ String.valueOf(lengthBefore));*/
if ((lengthBefore < lengthAfter) || lengthBefore == 0)
{
if (!isResetClicked)
{
if (s.length() == 0)
{
editPhoneNumber.setText("(");
}
if (s.length() == 1)
{
str = editPhoneNumber.getText().toString();
editPhoneNumber.setText("(" + str);
editPhoneNumber.setSelection(editPhoneNumber
.getText().length());
}
if (s.length() == 4)
{
str = editPhoneNumber.getText().toString();
editPhoneNumber.setText(str + ") ");
editPhoneNumber.setSelection(editPhoneNumber
.getText().length());
}
if (s.length() == 9)
{
str = editPhoneNumber.getText().toString();
editPhoneNumber.setText(str + " ");
editPhoneNumber.setSelection(editPhoneNumber
.getText().length());
}
if (s.length() == 12)
{
str = editPhoneNumber.getText().toString();
editPhoneNumber.setText(str + " ");
editPhoneNumber.setSelection(editPhoneNumber
.getText().length());
}
}
}
lengthAfter = s.length();
/*Log.i("ED", "LengthAfter after (lengthAfter = s.length();): "
+ String.valueOf(lengthAfter));
Log.i("ED", "LengthBefore: " + String.valueOf(lengthBefore));
Log.i("ED", "LengthAfter: " + String.valueOf(lengthAfter));*/
}