这是来自here的Spring安全登录示例。我将注释配置更改为XML,并且对应该指向的URL进行了一些更改。我能够成功登录db中的凭据。如果我输入错误的密码我收到无效的消息。但是如果我输入一个不在db中的用户名或只是提交没有值的用户名,我会得到nullpointerexception。
java.lang.NullPointerException
com.xxxx.service.CustomUserDetailsService.loadUserByUsername(CustomUserDetailsService.java:37)
sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
java.lang.reflect.Method.invoke(Method.java:606)
CustomUserDetailsService.java
@Service
@Transactional(readOnly=true)
public class CustomUserDetailsService implements UserDetailsService {
@Autowired
private LoginDAO loginDAO;
public UserDetails loadUserByUsername(String userName)
throws UsernameNotFoundException {
com.xxxx.model.Login domainUser = loginDAO.getUser(userName);
boolean enabled = true;
boolean accountNonExpired = true;
boolean credentialsNonExpired = true;
boolean accountNonLocked = true;
return new User(
domainUser.getUserName(), // line 37
domainUser.getPassword(),
enabled,
accountNonExpired,
credentialsNonExpired,
accountNonLocked,
getAuthorities(domainUser.getRole().getId())
);
}
public Collection<? extends GrantedAuthority> getAuthorities(Integer role) {
List<GrantedAuthority> authList = getGrantedAuthorities(getRoles(role));
return authList;
}
public List<String> getRoles(Integer role) {
List<String> roles = new ArrayList<String>();
if (role.intValue() == 1) {
roles.add("ROLE_MODERATOR");
roles.add("ROLE_ADMIN");
} else if (role.intValue() == 2) {
roles.add("ROLE_MODERATOR");
}
return roles;
}
public static List<GrantedAuthority> getGrantedAuthorities(List<String> roles) {
List<GrantedAuthority> authorities = new ArrayList<GrantedAuthority>();
for (String role : roles) {
authorities.add(new GrantedAuthorityImpl (role));
}
return authorities;
}
}
弹簧security.xml文件
<http auto-config="true">
<intercept-url pattern="/success" access="ROLE_MODERATOR" />
<intercept-url pattern="/success" access="ROLE_ADMIN" />
<form-login login-page="/login.html"
default-target-url="/success.html"
authentication-failure-url="/error.html" />
<logout logout-success-url="/login.html" />
</http>
<authentication-manager>
<authentication-provider user-service-ref="customUserDetailsService">
<password-encoder hash="plaintext" />
</authentication-provider>
</authentication-manager>
</beans:beans>
请有人指出我做错了。
编辑: LoginDAOImpl.java
@Repository
public class LoginDAOImpl implements LoginDAO {
@Autowired
private SessionFactory sessionFactory;
private Session openSession() {
return sessionFactory.getCurrentSession();
}
public Login getUser(String userName) {
List<Login> loginList = new ArrayList<Login>();
Query query = openSession().createQuery(
"from Login l where l.userName = :userName");
query.setParameter("userName", userName);
loginList = query.list();
if (loginList.size() > 0)
return loginList.get(0);
else
return null;
}
}
答案 0 :(得分:1)
问题是您正在尝试访问userName
null
个对象的Login
字段。
正如我所看到的,如果用户名不在数据库中,那么您将从DAO返回null
,但您没有在服务中检查返回值。
因此,在创建新的User
实例之前,请检查返回Login
是否为空。如果是null
,您应该抛出UsernameNotFoundException
。
答案 1 :(得分:0)
在您的应用程序上下文(app-context.xml文件)中尝试此操作或尝试其他xml文件。
<context:annotation-config/>