Question

 for (;;)
{
    cout << "You are playing for:" << playtime << "seconds." << endl;
    cout << "You have " << bytes << " bytes." << endl;
    cout << "You are compiling " << bps << " bytes per second." << endl;
    cout << "Press a to buy assembler monkey (produces 1 byte per second)/(cost 10 bytes)" << endl;
    switch(getch())
    {
        case 'a': bytes = bytes - 10; bps++; break;
    }
    bytes = bytes + bps;
playtime++;
Sleep(1000);
system("cls");
}

让我们说这是我的增量游戏。我想在1秒后刷新我的游戏。如何让getch（）等待输入而不停止所有其他东西？

Answer 1

使用 khbit（）函数检测是否按下了某个键：）

类似的东西：

 for (;;)
{
    cout << "You are playing for:" << playtime << "seconds." << endl;
    cout << "You have " << bytes << " bytes." << endl;
    cout << "You are compiling " << bps << " bytes per second." << endl;
    cout << "Press a to buy assembler monkey (produces 1 byte per second)/(cost 10 bytes)" << endl;
    if(kbhit()){  //is true when a key was pressed
        char c = getch();   //capture the key code and insert into c

        switch(c)
        {
            case 'a': bytes = bytes - 10; bps++; break;
        }
    }
    bytes = bytes + bps;
    playtime++;
    Sleep(1000);
    system("cls");
}

Answer 2

您可以使用其他线程来获取用户输入。

for (;;)是不必要的，您应该使用while (true)。

#include <Windows.h>
#include <iostream>
#include <conio.h>

using namespace std;

DWORD WINAPI SpeedThread(LPVOID lpParam);



int main ()
{
    int playtime = 0,
        bytes = 0,
        bps = 1;

    bool bKeyPressed = false;

    CreateThread( NULL, 0, SpeedThread, &bKeyPressed, 0, NULL);

    while (true)
    {
        cout << "You are playing for:" << playtime << "seconds." << endl;
        cout << "You have " << bytes << " bytes." << endl;
        cout << "You are compiling " << bps << " bytes per second." << endl;
        cout << "Press a to buy assembler monkey (produces 1 byte per second)/(cost 10 bytes)" << endl;
        if (bKeyPressed && bytes >= 10)
        {
            bytes -= 10;    
            bps++; 

            bKeyPressed = false;
        }
        bytes = bytes + bps;
        playtime++;
        Sleep(1000);
        system("cls");
    }

}

DWORD WINAPI SpeedThread (LPVOID lpParam)
{
    bool * bKeyPressed = (bool *) lpParam;

    while (true)
    {
        if (_getch () == 'a')
            *bKeyPressed = true;
    }
}

Answer 3

对我有用的不是使用getch()，而是使用scanf()。为了阻止scanf停止运行，您必须使用：

scanf("%c \n",example);

请记住，example是指针（char* example;）

如何使用getch（）而不等待输入？

3 个答案: