使用<http ... />
Spring Security 3命名空间时,如何自定义UsernamePasswordAuthenticationFilter usernameParameter(j_username)和passwordParameter(j_password)属性?我的理解是<http ... />
创建了过滤器,但我没有看到如何自定义它。
答案 0 :(得分:4)
以下是我根据axtavt的建议创建的解决方案:
Spring配置:
<beans:bean id="userPassAuthFilterBeanPostProcessor"
class="com.my.package.UserPassAuthFilterBeanPostProcessor">
<beans:property name="usernameParameter" value="username" />
<beans:property name="passwordParameter" value="password" />
</beans:bean>
Java类:
package com.my.package;
import org.springframework.beans.factory.config.BeanPostProcessor;
import org.springframework.security.web.authentication.
UsernamePasswordAuthenticationFilter;
public class UserPassAuthFilterBeanPostProcessor implements BeanPostProcessor {
private String usernameParameter;
private String passwordParameter;
@Override
public final Object postProcessAfterInitialization(final Object bean,
final String beanName) {
return bean;
}
@Override
public final Object postProcessBeforeInitialization(final Object bean,
final String beanName) {
if (bean instanceof UsernamePasswordAuthenticationFilter) {
final UsernamePasswordAuthenticationFilter filter =
(UsernamePasswordAuthenticationFilter) bean;
filter.setUsernameParameter(getUsernameParameter());
filter.setPasswordParameter(getPasswordParameter());
}
return bean;
}
public final void setUsernameParameter(final String usernameParameter) {
this.usernameParameter = usernameParameter;
}
public final String getUsernameParameter() {
return usernameParameter;
}
public final void setPasswordParameter(final String passwordParameter) {
this.passwordParameter = passwordParameter;
}
public final String getPasswordParameter() {
return passwordParameter;
}
}
答案 1 :(得分:1)
使用form-login元素配置过滤器,但该元素不提供为用户名和密码设置自定义名称的功能。
您可以直接配置,如Spring Reference
中所述