Question

嘿我需要帮助解决这个错误我有 **注意：未定义的变量：第16行的C：\ xampp \ htdocs \ ZoomiezWebApp \ addNewCustomer.php中的反馈** 。我正在尝试创建一个表单来添加新客户。

这是代码

 <?php
  #1> Retrieve Form Details
  $fname= $_POST['fname'];
  $lname= $_POST['lname'];
  $address= $_POST['address'];
  $cNumber= $_POST['contactNumber'];


  #2 SANITIZE AND VALIDATE DATA
  $fname = filter_var($fname, FILTER_SANITIZE_STRING);
  $lname = filter_var($lname, FILTER_SANITIZE_STRING);
  $address = filter_var($address, FILTER_SANITIZE_STRING);
  $cNumber = filter_var($cNumber, FILTER_SANITIZE_STRING);

if($fname==""){//Validate fields for null or empty
    ***ERROR IS IN THIS LINE***$feedback .= "<br>First Name Field Empty.";
}if($lname==""){
    $feedback .= "<br>Last Name Field Empty.";
}if($address==""){
    $feedback .= "<br>Address Field Empty.";
}if($cNumber==""){
    $feedback .= "<br>Contact Number Field Empty.";
}else{ //Validation Passed...


    // #3> CONNECT MYSQL ON THE DB SERVER /
    $con = mysql_connect('localhost', "root", "test")
    or die ('Could not connect to the database');

    // #4> SELECT THE DATABASE ON THE SERVER /
    $con = mysql_select_db('zoomiezdb', $con)
    or die ('Could not locate database');

    // #5> CREATE INSERT QUERY
    $addCustomerQuery = 
        "INSERT INTO customertable (First Name, Last Name, Address, Contact Number) VALUES ('$fname', '$lname', '$address', '$cNumber'))                                                                     ";

    // #6> EXECUTE QUERY
    $queryResult = mysql_query($addCustomerQuery);

    // #7> VERIFY IF QUERY IS SUCCESSFUL
    if($queryResult)    
        $feedback = "New Customer Added";
    else
        $feedback = "<i>Add New Customer was Unsuccessful.</i>
                <br>    
                Please Contact Site Administrator...";  


    // #8> REDIRECT
 Header("Location:newCustomer.php?feedbackMsg=$feedback");

}

＆GT？;

Answer 1

如果没有错误，你应该在条件之前初始化那个变量$ feedback永远不会初始化，在这种情况下你可以用＆＃39;＆＃39;来初始化它。因为当你连接它时，PHP没有任何东西可以连接

使用localhost时，php未定义变量

1 个答案: