ORA-00905 MISSING KEYWORD在case语句中。虽然语法是正确的

Question

我为查询找到了丢失的关键字错误ORA-00905

SELECT '01_AMT' AS FIELD, COUNT((NVL(AMT,0)) AS CNT FROM  TBL1

UNION ALL

SELECT 

CASE 
WHEN  AMT IS NULL THEN 'NULL'

WHEN AMT<10000 THEN '<10000'

WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999’

ELSE '60,000up' END,


COUNT (1) CNT FROM TBL1

GROUP BY CASE

WHEN  AMT IS NULL THEN 'NULL'

WHEN AMT<10000 THEN '<10000'

WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999’

ELSE '60,000up' END

输出：

FIELD CNT

01_Amt 100000

10,000-59,999 50000

60,000up 50000

第一个字段＆＃39; 01-Amt＆＃39;应该具有第二行中其他计数的总计数和细分。 Amt是数字数据类型。

Answer 1

你没有使用标准的结束标记，而是那个卷曲标记。 Oracle不理解它，它忽略了句子的其余部分。校正：

SELECT '01_AMT' AS FIELD, COUNT((NVL(AMT,0)) AS CNT FROM  TBL1

UNION ALL

SELECT 

CASE 
WHEN  AMT IS NULL THEN 'NULL'

WHEN AMT<10000 THEN '<10000'

WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999' <= CHANGED THIS TICK!

ELSE '60,000up' END,


COUNT (1) CNT FROM TBL1

GROUP BY CASE

WHEN  AMT IS NULL THEN 'NULL'

WHEN AMT<10000 THEN '<10000'

WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999' <= CHANGED THIS TICK!

ELSE '60,000up' END