将XML转换为JSON跳过根元素

Question

我必须将xml转换为JSON。我已经以下面的方式实现了

import net.sf.json.JSON;
import net.sf.json.JSONSerializer;
import net.sf.json.xml.XMLSerializer

XMLSerializer xmlSerializer = new XMLSerializer();
//xmlSerializer.setForceTopLevelObject(true);
//Above line is comented since i want to skip xml root element
JSON json = xmlSerializer.read(inputXml);
outJSON = json.toString(2);

我的输入xml是

<details>
    <name>
        <firstName>sir</firstName>
        <lastName>John</lastName>
        <midddleName>Nash</midddleName>
    </name>
    <address>24525 ross street</address>
</details>

我的输出JSON是，它可以很好地跳过根元素

{
  "name":   {
    "firstName": "sir",
    "lastName": "John",
    "midddleName": "Nash"
  },
  "address": "24525 ross street"
}

但是当我提出请求时

<details>
    <name>
        <firstName>sir</firstName>
        <lastName>John</lastName>
        <midddleName>Nash</midddleName>
    </name>
</details>

我的JSON回复是

[
  {
    "firstName": "sir",
    "lastName": "John",
    "midddleName": "Nash"
  }
]

但我需要回复

{
  "name":   {
    "firstName": "sir",
    "lastName": "John",
    "midddleName": "Nash"
  }
}

即使有任何其他API提供此功能，请建议我