据我所知,我实现了一个在新线程上创建的runnable。但是,该线程似乎并未在后台运行,并且在runnable中执行的操作正在以大量操作停止UI。
见下文:
custListLoadThread = new Thread(loadRunnable);
custListLoadThread.run();
private Runnable loadRunnable = new Runnable()
{
@Override
public void run()
{
android.os.Process.setThreadPriority(android.os.Process.THREAD_PRIORITY_BACKGROUND);
Gen.popup("TEST"); // Creates a toast pop-up.
// This is to know if this runnable is running on UI thread or not!
try
{
customers = Db.BasicArrays.getCustomers(CustomApp.Session.businessCode, empId);
runOnUiThread(new Runnable() {
@Override
public void run() {
populate();
setCustListVisible(true);
loading = false;
}
});
}
catch (final Exception ex)
{
runOnUiThread(new Runnable() {
@Override
public void run() {
Gen.popup(ex.getMessage());
}
});
}
}
};
但是这段代码不在后台运行,它似乎仍然在UI线程上运行。我已经放置了行Gen.popup("TEST");
来确保这一点(在非UI线程中调用toast
弹出应该会导致错误。)
关于为什么这个runnable没有在后台运行的任何想法?
答案 0 :(得分:23)
custListLoadThread = new Thread(loadRunnable);
custListLoadThread.start();
你需要启动线程,而不是在当前线程中调用run()方法。
答案 1 :(得分:11)
如果要在后台线程上执行代码,该代码不对UI执行任何操作:
curl -L -H 'Content-Type: application/json' -X POST chronos-node:8080/scheduler/iso8601 -d '
{
"schedule": "R/2016-04-15T12:00:00Z/PT2M",
"name": "spark-submit-job",
"container": {
"type": "DOCKER",
"image": "my/sparksubmitapp",
"network": "BRIDGE",
"forcePullImage": true
},
"cpus": "0.5",
"mem": "1024",
"uris": [],
"command": "/path/to/spark/bin/spark-submit --class com.my.app.Main myApp.jar"
}'
当然,如前所述,您还可以创建一个新线程(独立于UI线程):
Runnable runnable = new Runnable() {
@Override
public void run() {
//your action
}
};
AsyncTask.execute(runnable);
在您的示例中,您想要更新UI元素,因此最好使用 new Thread(runnable).start();
(必须从UI线程调用!):
AsyncTask