Question

这里有一些SQL：

select T.*
FROM (
values ( '2014-05-30 17:26:32.749' , 'Casual shirt ' ) , ( '2014-05-30 17:26:32.749' , 'Casual shirt-White-Small ' ) , ( '2014-05-30 17:26:32.749' , 'Casual shirt-Blue-Medium ' ) , ( '2014-05-30 17:26:32.749' , 'Cords ' ) , ( '2014-05-30 17:26:32.749' , 'Bodysuit ' ) , ( '2014-05-30 17:26:32.749' , 'Cords-Black-29W x 28L ' ) , ( '2014-05-30 17:26:32.749' , 'Bodysuit-Black-Petit ' ) , ( '2014-05-30 17:26:32.749' , 'Cords-Brown-29W x 28L ' ) , ( '2014-05-30 17:26:32.749' , 'Classic pleated dress pant ' ) , ( '2014-05-30 17:26:32.749' , 'Classic pleated dress pant-Black-29W x 32L ' ) , ( '2014-05-30 17:26:32.749' , 'Dress shirt ' ) , ( '2014-05-30 17:26:32.749' , 'Dress shirt-White-15 ' ) , ( '2014-05-30 17:26:32.749' , 'Dress shirt-White-16 ' )
) T
;

它返回列＆＃34; 1＆＃34;和＆＃34; 2＆＃34;。如何更改它以便返回命名列？是否可以不使用sysdummy1？

Answer 1

您可以将列名添加到T：

select T.*
FROM (values ( '2014-05-30 17:26:32.749' , 'Casual shirt ' ) ,
             ( '2014-05-30 17:26:32.749' , 'Casual shirt-White-Small ' ) ,
             ( '2014-05-30 17:26:32.749' , 'Casual shirt-Blue-Medium ' ) ,
             ( '2014-05-30 17:26:32.749' , 'Cords ' ) ,
             ( '2014-05-30 17:26:32.749' , 'Bodysuit ' ) ,
             . . .
     ) T(col1, col2);

VALUES（）语法的列别名

1 个答案: