Question

我有下一个代码

class MySystem(outerResourse: OuterResourse) extends Actor {

  val firstActor = context.actorOf(Props(new FirstActor(outerResourse)), "first")

  val secondActor = context.actorOf(Props(new SecondActor(firstActor)), "second")

  secondActor ! Go

  def receive = {
    case x: AnotherMessage => printl(s"another message: $x")
    case x => println(x)  
  }
}


class FirstActor(outerResourse: OuterResourse) extends Actor {
  def receive = {
   case Test => 
     context.parent ! AnotherMessage 
     sender ! "ok"
  }
}

class SecondActor(firstActor: ActorRef) extends Actor {
  def receive = {
    case Go => firstActor ! Test
    case "ok" => println("ok")
  }
}

此处OuterResourse是任何资源 - 文件，互联网连接......

我想查看一个行为，但我很尴尬，我不知道如何检查第二个演员是否会得到一个＆＃34; ok＆＃34;和mySystem演员将得到一个AnotherMessage

class MyTest(_system: ActorSystem) extends TestKit(_system)
  with ImplicitSender with FunSpecLike with Matchers {

  def this() = this(ActorSystem("myTest"))

  val outerResourse = new OuterResourse()
  val mySystem = system.actorOf(Props(new MySytem(outerResourse)))

  describe("Actors") {
    it("should get AnotherMessage message and ok message") {
      ???
    }
  }
}

热门检查，secondActor得到了一个＆＃34;确定＆＃34;信息？

Answer 1

您可以为OutputStream usnig println设置自定义Console.withOut。它可能是模拟并“等待”来自第一个演员的OK消息。但它不是很好......

//编辑：请阅读文档http://doc.akka.io/docs/akka/snapshot/scala/testing.html Akka提供他们测试“框架”

测试演员系统

1 个答案: