Question

我在DESKTOP浏览器（Chrome for Linux）上运行此代码：

var deviceReadyDeferred = $.Deferred();
var jqmReadyDeferred = $.Deferred();
document.addEventListener("deviceReady", onDeviceReady, false);
function onDeviceReady() {
        deviceReadyDeferred.resolve();
}
$(document).one("mobileinit", function () {
        console.log('JQM is ready');
        jqmReadyDeferred.resolve();
});
$.when(deviceReadyDeferred, jqmReadyDeferred).then( doWhenBothFrameworksLoaded(), failure() );
function doWhenBothFrameworksLoaded() {
            alert('success :deviceReadyDeferred is '+deviceReadyDeferred.state());
            console.log('Phonegap and JQM are loaded');
            EVERYTHING();
}

并且alert给出了success :deviceReadyDeferred is pending ...而它甚至不应该开火，是吗？

感谢您的帮助。

Answer 1

您需要将函数引用作为参数传递给then()方法，不要在调用then()时调用回调方法（通过在函数名末尾添加()）

$.when(deviceReadyDeferred, jqmReadyDeferred).then(doWhenBothFrameworksLoaded, failure);

演示：Fiddle

jquery .when（）触发完成回调，而延迟对象处于挂起状态

1 个答案: