由ArrayList填充的JTable,结果不好

时间:2014-07-18 01:06:25

标签: java swing arraylist jtable tablemodel

我必须使用JTable填充ArrayList,但是当表格显示时,除了正确的信息外,还会填充其他内容。您可以点击下一个链接查看我的表格的外观。

table

gui1是主类的名称,theObject是包含要在表上显示的信息结构的类的名称。

请帮我解决这个问题!!

ArrayList定义:

 static ArrayList<theObject> datos = new ArrayList<theObject>();

这是用于加载名为“datos”的ArrayList的代码:

试试{// ------------------------ carga registros de proyectos --------------- -------------

        contador = 0;
        fr = new FileReader(file);
        br = new BufferedReader(fr);
        while ((cadena1 = br.readLine()) != null){

            datos1 [0] = cadena1.substring(0,8);
            datos1 [1] = cadena1.substring(8,38);
            datos1 [2] = cadena1.substring(38,52);
            datos1 [3] = cadena1.substring(52,57);
            datos1 [4] = cadena1.substring(57,62);
            datos1 [5] = cadena1.substring(62,72);
            datos1 [6] = cadena1.substring(72,77);
            datos1 [7] = cadena1.substring(77,82);
            datos1 [8] = cadena1.substring(82,89);
            datos1 [9] = cadena1.substring(89,94);
            datos1 [10] = cadena1.substring(94,239);

            datos.add(new theObject(datos1));
            contador ++;


        }

        br.close();

    }
    catch (IOException e) {
        e.printStackTrace();
    }

该表填充了以下行:

tabla = new JTable(new MyModel(datos));

现在代码中涉及的类:

class theObject {
    String sap,cte,pep,dis1,dis2,norma,nvent,ntc,tmando,tparalel,equip;

    theObject(String dato[]) {
        this.sap = dato[0];
        this.cte = dato[1];
        this.pep = dato[2];
        this.dis1 = dato[3];
        this.dis2 = dato[4];
        this.norma = dato[5];
        this.nvent = dato[6];
        this.ntc = dato[7];
        this.tmando = dato[8];
        this.tparalel = dato[9];
        this.equip = dato[10];
    }

}

class MyModel extends AbstractTableModel {

    private String[] columnNames = { "FERT","CLIENTE ","PEP","A","B","C","D","E","F","G","H" };

    ArrayList<theObject> arr1 = null;

    MyModel(ArrayList<theObject> arr1) {

        this.arr1 = arr1;
    }
    public int getColumnCount() {
        return columnNames.length;
    }

    public int getRowCount() {
        return pru2.datos.size();
    }

    public Object getValueAt(int row, int col) {

        theObject a1 = datos.get(row);


        return a1;
    }
}

在Eclipse中编译后我没有错误,所以我无法识别问题

1 个答案:

答案 0 :(得分:1)

您获得gui$theObject@4ab60e21每个单元格的原因是因为您要返回theObject中的整个getValueAt(),而theObject只返回字段 public class TheObject { // please notice the Naming convention // and follow it. Class begins with capital private fert; private cliente; private pep; // getter and setters } 例如,您的课程如下所示

getValueAt()

private String[] columnNames = { "FERT","CLIENTE ","PEP" }; private ArrayList<TheObject> data; ... public Object getValueAt(int row, int col) { Object value = null; TheObject obj = data.get(row); switch(col) { case 0: value = obj.getFert(); break; case 1: value = obj.getCliente(); break; case 2: value = obj.getPep(); break; default: break; } return value; } 中的值应该根据col返回其中一个字段。例如

TheObject

因此,您的单元格值不会只是TheObject的字段,而不是整个{{1}}对象的字段。