我第一次使用Jquery FormData,但似乎缺少一些东西。在JS-postAjax方法中,当调用新的FormData()时,它只是跳过剩余的行并转到函数的末尾而没有任何错误。我在这里做错了什么?
template.js //按此顺序编写脚本文件
<script src="js/jquery-2.1.0.js"></script>
<script src="js/jquery.form.js"></script>
<script src="js/bootstrap.js"></script>
<script src="js/bootstrapValidator.js"></script>
<script src="js/hemoncCBCFunctions.js"></script>
<script src="js/validations.js"></script>
JSP
<form name ="newSectionSubmitForm" id="newSectionSubmitForm" class="form-horizontal" role="form" method="post" ENCTYPE="multipart/form-data">
<table>
<tr>
<td>
<input type="file" id='imageFile0' name='imageFile0' class="form-control" />
</td>
</tr>
</table>
<form>
JS
function submitNewSection(targetUrl, form) {
postAjaxData(null, 'content', targetUrl, form, null, null);
}
function postAjaxData(initiatingElement, targetElement, targetUrl, form,
additionalParamMap, successCallback) {
var $targetElement = $('#' + targetElement);
var serializedFormData;
serializedFormData = $('#' + form).serialize();
for ( var j in additionalParamMap) {
serializedFormData += "&" + j + "=" + additionalParamMap[j];
}
alert('serialized form data ' + serializedFormData);
var formData = new FormData(serializedFormData);//**exits the function no errors**
formData.append("file", $('#imageFile0').files[0]);
alert('serialized form data ' + formData);
$.ajax({
type : "POST",
cache : false,
data : formData,
url : targetUrl,
success : function(data) {
processRedirect(data);
$targetElement.html(data);
$targetElement.show();
if (successCallback != null) {
successCallback(data);
}
},
error : function(xhr, httpRequest, textStatus, errorThrown) {
var errorId = xhr.getResponseHeader("errorId");
var errorMsg = xhr.getResponseHeader("errorMessage");
if (errorId != null && errorId != undefined) {
$("#page_error").html(
"An unexpected error has occurred. Error Id: "
+ errorId);
} else {
$("#page_error").html("An unexpected error has occurred.");
}
},
});
控制器文件(但代码无法到达此处)
@RequestMapping(value = "/submitNewSection.html")
public String submitNewSection( MultipartHttpServletRequest req, HttpServletRequest request, Model model) {
Iterator<String> itr = req.getFileNames();
MultipartFile mpf = req.getFile(itr.next());
System.out.println("file name " + mpf.getOriginalFilename() +" uploaded!");
}
非常感谢。