Question

如何更新我的SQL表以显示上次登录日期？我试过“UPDATE表SET user_last_login =”'date（“m.d.y”）'“WHERE $ user_name”，但表没有更新。如果我单击表格列，它会将其更改为当前日期。

SQL表：

CREATE TABLE IF NOT EXISTS `users` (
    `id` int(100) NOT NULL AUTO_INCREMENT,
    `user_name` varchar(10) COLLATE utf8_unicode_ci NOT NULL,
    `user_pass` varchar(50) COLLATE utf8_unicode_ci NOT NULL,
    `user_rank` varchar(50) COLLATE utf8_unicode_ci NOT NULL DEFAULT 'Member',
    `user_ip` varchar(15) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL,
    `user_last_login` date NOT NULL,
     PRIMARY KEY (`id`)
   ) ENGINE=MyISAM  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=4 ;

PHP：

if(isset($_POST['login'])){

$name = $_POST['name'];
$password = $_POST['pass'];

$check_user = "select * from users where user_name='$name' AND user_pass='".md5($_POST['pass'])."'";

$run = mysql_query($check_user);

if(mysql_num_rows($run)>0){


//Create query
$qry="SELECT * FROM users WHERE user_name='$name' AND user_pass='".md5($_POST['pass'])."'";
$result=mysql_query($qry);

$update="UPDATE table SET user_last_login="'date("m.d.y")'"

//Check whether the query was successful or not
if($result) {
    if(mysql_num_rows($result) == 1) {
        //Login Successful
        session_regenerate_id();
        $users = mysql_fetch_assoc($result);
        $_SESSION['id'] = $users['id'];
        $_SESSION['name'] = $users['user_name'];
        $_SESSION['pass'] = $users['user_pass'];
        $_SESSION['rank'] = $users['user_rank'];
        $_SESSION['ip'] = $users['user_ip'];
        session_write_close();
    }
}
}

Answer 1

在session_start（）;

if($_SERVER["REQUEST_METHOD"] == "POST") {
    // username and password sent from form 
    // $db is connection to database

    $myusername = mysqli_real_escape_string($db,$_POST['username']);
    $mypassword = mysqli_real_escape_string($db,$_POST['password']); 

    $sql = "SELECT id FROM users WHERE username = '$myusername' and password = '$mypassword'";
    $result = mysqli_query($db,$sql);
    $row = mysqli_fetch_array($result,MYSQLI_ASSOC);

    $count = mysqli_num_rows($result);

    // If result matched $myusername and $mypassword, table row must be 1 row

    if($count == 1) {
        //session_register("myusername");
        $_SESSION['login_user'] = $myusername;

        header("location: account.php");
        }else {
        echo $error = "Your Login Name or Password is invalid";
    }

    $t_sql = "UPDATE users SET login_time=CURRENT_TIMESTAMP WHERE username = '$myusername'";
    $t_result = mysqli_query($db,$t_sql); 
}

Answer 2

WHERE $user_name

应该是

WHERE user_name=$user_name

你当前的查询是我假设的错误。

Answer 3

您需要插入MySql日期格式：

是2012-01-01 = YYYY-MM-DD

而不是m.d.y

Answer 4

您的代码中存在一些错误。

首先，你把你的POST值放在一个变量中，你永远不会使用它！

$name = $_POST['name'];
$password = $_POST['pass'];

你可以做到

$name = $_POST['name'];
$password = md5($_POST['pass']);
$check_user = "select * from users where user_name='$name' AND user_pass='$password'";

为什么要使用下一行代码？

$qry="SELECT * FROM users WHERE user_name='$name' AND user_pass='".md5($_POST['pass'])."'";

并更新您的数据库。请尝试以下代码。

$date = date('Y-m-d');
$update="UPDATE table SET user_last_login='$date' WHERE user_name='$name' AND user_pass='$password'";"

如何更新上次登录时间（PHP＆amp; SQL）？

SQL表：

PHP：

4 个答案: