Oracle SQL - 简化总计列

Question

我有以下问题需要解决：

1. 有没有办法简化Total列？
2. 底行显示为null，我希望它也是“Total”。
3. 以我的方式ROLLUP，ROLLUP（（状态））更好吗？或者这与ROLLUP（状态）完全相同？

以下是我的询问：

SELECT
        status AS "ROW LABELS",
        COUNT(case when source = 'INTERNET' THEN 1 end) AS "INTERNET",
        COUNT(case when source = 'SALES' THEN 1 end) AS "SALES",
        COUNT(case when source = 'REP' THEN 1 end) AS "REP",
        COUNT(case when source = 'COM' THEN 1 end) AS "COM",
        (COUNT(case when source = 'INTERNET' THEN 1 end) +
        COUNT(case when source = 'SALES' THEN 1 end) +
        COUNT(case when source = 'REP' THEN 1 end) +
        COUNT(case when source = 'COM' THEN 1 end)
        ) AS Total
FROM
SOMETABLE
GROUP BY ROLLUP((status))
order by 1;

以下是我的数据：

Answer 1

1. 如果通过＆＃34;简化＆＃34;你的意思是＆＃34;使计算更简洁＆＃34;然后是。以下内容适用：

   COUNT(CASE WHEN source IN ('INTERNET', 'SALES', 'REP', 'COM') THEN 1 END)
   

2. 只需使用nvl将NULL转换为值：NVL(status, 'TOTAL') AS row_labels

3. ROLLUP( (status) )与ROLLUP( status )

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