我是一名对Java缺乏了解的初学者。我使用Dr.Java,我收到了这个错误:
"S cannot be resolved"
使用这个Java程序:
import java.util.Scanner;
public class HDtest5
{
public static int countWords(String str) {
String words[] = str.split(" ");
int count = words.length;
return count;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a sentence: ");
String sentence = in.nextLine();
System.out.print("Your sentence has " + countWords(sentence) + " words.");
}
{
while (true) // have created infinite loop
{
if (s.equals("quit"))
// if enterd value is "quit" than it comes out of loop
{
String[] words = s.split(" "); // get the individual words
System.out.println("#words = " + words.length);
for (int i = 0; i < words.length; i++)
System.out.println(s + "word[" + i + words[i] + " nchars = " + words[i].length());
}
System.out.println(s); // to Print string
System.out.println(s.length()); // to print Entered string's length
}
}
}
导致此错误消息的原因是什么? 我认为所有的字符串都叫做&#39; s&#39;应该没有任何问题地一起工作。你能帮我找一下它有什么问题吗?非常感谢您的帮助,非常感谢!
聚苯乙烯。为了更清楚,我的程序的目的是输出字符总数,每个单词的字符和在文本窗口(扫描仪)中输入的文本的单词数。代码应该完美地工作,除了这个&#39;字符串问题,使得代码块不能一起工作。
答案 0 :(得分:1)
在Java中,您必须先在之前声明一个变量,然后才能使用它。
缺少一行代码:
String s;
顺便说一下,你可能想要使用sentence
代替s
,正如其他人注意到的那样。可能的值"quit"
将位于sentence
变量中。
通过声明变量:
String personName;
你说编译器:
从现在开始,将
personName
理解为能够存储String
的内存。
编译器将为您完成一项伟大的工作 - 它不会让您分配给personName
任何其他内容(例如int
),如果您输入错字并在某处写personMame
,你会立即找到它,而不是在运行时很晚,你不知道为什么你的代码不起作用,就像在JavaScript中一样。
答案 1 :(得分:1)
你还没有在代码中声明s
。在String s=null;
方法的开头写上这样的内容,main()
,然后在代码后面给它一些值
答案 2 :(得分:1)
你得到这个错误,因为你没有声明任何变量S但你在if条件下使用它。你也错误地放置了{}大括号。 将主要方法改为:
注意:你的编程在infinte循环中运行。
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a sentence: ");
String s = in.nextLine();
System.out.print("Your sentence has " + countWords(s) + " words.");
while (true) // have created infinite loop
{
if (s.equals("quit"))
// if enterd value is "quit" than it comes out of loop
{
String[] words = s.split(" "); // get the individual words
System.out.println("#words = " + words.length);
for (int i = 0; i < words.length; i++)
System.out.println(s + "word[" + i + words[i]
+ " nchars = " + words[i].length());
}
System.out.println(s); // to Print string
System.out.println(s.length()); // to print Entered string's length
}
}
答案 3 :(得分:1)
我认为您想要使用sentence
变量。
并且您不会为while循环的每次迭代读取变量。
也许你想要更多这样的东西。
public class HDtest5 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (true) { // have created infinite loop
System.out.print("Enter a sentence: ");
String sentence = in.nextLine();
System.out.print("Your sentence has " + countWords(sentence) + " words.");
if (sentence.equals("quit")) { // if enterd value is "quit" than it comes out of loop
break;
} else {
String[] words = sentence.split(" "); // get the individual words
System.out.println("#words = " + words.length);
for (int i = 0; i < words.length; i++)
System.out.println(sentence + "word[" + i + words[i] + " nchars = " + words[i].length());
}
System.out.println(sentence); // to Print string
System.out.println(sentence.length()); // to print Entered string's length
}
in.close();
}
private static int countWords(String str) {
String words[] = str.split(" ");
int count = words.length;
return count;
}
}
答案 4 :(得分:1)
我想我想出了你想要实现的目标并修复了你的代码:
import java.util.Scanner;
public class HDtest5
{
public static int countWords(String str) {
String words[] = str.split(" ");
int count = words.length;
return count;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (true) // have created infinite loop
{
System.out.print("Enter a sentence: ");
String sentence = in.nextLine();
if (sentence.equals("quit")) {
// if enterd value is "quit" than it comes out of loop
break;
}
System.out.print("Your sentence has " + countWords(sentence) + " words.");
String[] words = sentence.split(" "); // get the individual words
System.out.println("#words = " + words.length);
for (int i = 0; i < words.length; i++)
System.out.println("word[" + i + "] = " + words[i] + " nchars = " + words[i].length());
}
System.out.println(sentence); // to Print string
System.out.println(sentence.length()); // to print Entered string's length
}
in.close();
}
}