我正在尝试开发一个将 JSON 转换为 CSV 的应用程序。
我正在使用 JACKSON 解析 JSON 并撰写 CSV 。
以下是我要解析的 JSON 的示例:
{ "_id" : 0,
"name" : "aimee Zank",
"scores" :
[
{ "type" : "exam", "score" : 1.463179736705023 },
{ "type" : "quiz", "score" : 11.78273309957772 },
{ "type" : "homework", "score" : 6.676176060654615 },
{ "type" : "homework", "score" : 35.8740349954354 }
]
}
{ "_id" : 1,
"name" : "Aurelia Menendez",
"scores" :
[
{ "type" : "exam", "score" : 60.06045071030959 },
{ "type" : "quiz", "score" : 52.79790691903873 },
{ "type" : "homework", "score" : 71.76133439165544 },
{ "type" : "homework", "score" : 34.85718117893772 }
]
}
{ "_id" : 2,
"name" : "Corliss Zuk",
"scores" :
[
{ "type" : "exam", "score" : 67.03077096065002 },
{ "type" : "quiz", "score" : 6.301851677835235 },
{ "type" : "homework", "score" : 20.18160621941858 },
{ "type" : "homework", "score" : 66.28344683278382 }
]
}
两个Java类:
JsonNode类
public class JsonNode {
private String _id;
private String name;
private Collection<ScoreType> scores;
/**
* @return the _id
*/
public String get_id() {
return _id;
}
/**
* @param _id the _id to set
*/
public void set_id(String _id) {
this._id = _id;
}
/**
* @return the name
*/
public String getName() {
return name;
}
/**
* @param name the name to set
*/
public void setName(String name) {
this.name = name;
}
/**
* @return the scores
*/
public Collection<ScoreType> getScores() {
return scores;
}
/**
* @param scores the scores to set
*/
public void setScores(Collection<ScoreType> scores) {
this.scores = scores;
}
}
ScoreType类
public class ScoreType {
private String type;
private String score;
/**
* @return the type
*/
public String getType() {
return type;
}
/**
* @param type the type to set
*/
public void setType(String type) {
this.type = type;
}
/**
* @return the score
*/
public String getScore() {
return score;
}
/**
* @param score the score to set
*/
public void setScore(String score) {
this.score = score;
}
}
将 JSON 转换为 CSV
的方法 ObjectMapper mapper=new ObjectMapper();
JsonNode jsonNode=mapper.readValue(new File("C:\\...\\...\\...\\test.json"), JsonNode.class);
CsvMapper csvMapper=new CsvMapper();
CsvSchema schema=csvMapper.schemaFor(JsonNode.class);
schema=schema.withColumnSeparator(';');
ObjectWriter myObjectWriter=csvMapper.writer(schema);
FileOutputStream tempFileOutputStream=new FileOutputStream(out+"\\jsontocsv.csv");
BufferedOutputStream bufferedOutputStream=new BufferedOutputStream(tempFileOutputStream);
OutputStreamWriter writerOutputStream=new OutputStreamWriter(bufferedOutputStream,"UTF-8");
myObjectWriter.writeValue(writerOutputStream,jsonNode);
控制台输出:
com.fasterxml.jackson.core.JsonGenerationException: CSV generator does not support
属性的数组值
CSV输出:
"0";"aimee Zank";
到目前为止,这就是我所做的。
所以我在这里遇到两个问题:
1)输出CSV不完整,只创建一行而不写分数。
2)控制台中的错误。
我正在使用这些 JACKSON depandencies:
<dependency>
<groupId>com.fasterxml.jackson.dataformat</groupId>
<artifactId>jackson-dataformat-csv</artifactId>
<version>2.4.0</version>
</dependency>
有人可以帮我解决这些问题吗?
我希望我足够清楚。
编辑 CSV我期待:
_id;name;scores.type;scores.score;scores.type;scores.score;scores.type;scores.score
0;aimee Zank;exam;1.46;quiz;11.78;homework;6.67;homework;35.87
伊斯梅尔
答案 0 :(得分:1)
由于CSV是简单值的元组,因此它确实不支持集合(JSON数组)作为列值。您有一个Collection<ScoreType>
作为bean的一个属性,这会导致您的错误。
建议:添加String
getter,将您的集合转换为字符串,并手动构建CSV模式 ,以避免自动使用Collection-valued列。
答案 1 :(得分:0)
尝试对 JsonNode 类中的 Collection 属性使用自定义 json 序列化程序并将列表转换为字符串。
public class JsonNode {
private String _id;
private String name;
@JsonSerialize(using=CollectionSerializer.class)
private Collection<ScoreType> scores;
}
public class CollectionSerializer extends StdSerializer<Collection<Object>> {
private static final long serialVersionUID = 1L;
protected CollectionSerializer(Class<Collection<Object>> t) {
super(t);
}
public CollectionSerializer() {
this(null);
}
@Override
public void serialize(Collection<Object> value, JsonGenerator gen, SerializerProvider provider) throws IOException {
gen.writeString(value.stream().map(String::valueOf).collect(Collectors.joining(",")).toString());
}
}