我有一个数据库,其日期列的格式为dd / mm / yyyy,我想按日期按升序排序。
$cursor = $collection->find($filter)->sort(array('date' => 1, 'tripID' => 1));
日期是一个字符串,我也在对tripID进行过滤,但这方面是有效的。问题是目前我得到了:
01/01/2014
01/02/2014
02/01/2014
02/02/2014
我想要的是:
01/01/2014
02/01/2014
01/02/2014
02/02/2014
是否可以使用查询实现此目的,还是需要在应用程序中完成?
答案 0 :(得分:0)
假设我们在您的问题中给出了列表
> db.dates.insertMany([{ "date": "01/01/2014" },
{ "date": "01/02/2014" },
{ "date": "02/01/2014" },
{ "date": "02/02/2014" }])
{
"acknowledged" : true,
"insertedIds" : [
ObjectId("5a314eae330cc13d0c9b10c4"),
ObjectId("5a314eae330cc13d0c9b10c5"),
ObjectId("5a314eae330cc13d0c9b10c6"),
ObjectId("5a314eae330cc13d0c9b10c7")
]
}
在MongoDB 3.6中,我们可以使用聚合框架并使用$dateFromString
(https://docs.mongodb.com/manual/reference/operator/aggregation/dateFromString/)管道运算符将字符串日期转换为日期,然后对值进行排序:
> db.dates.aggregate([
{ "$project" : { "date" : { "$dateFromString" : { "dateString" : "$date"} } } },
{ "$sort" : { "date" : 1 } }
])
{ "_id" : ObjectId("5a314eae330cc13d0c9b10c4"), "date" : ISODate("2014-01-01T00:00:00Z") }
{ "_id" : ObjectId("5a314eae330cc13d0c9b10c5"), "date" : ISODate("2014-01-02T00:00:00Z") }
{ "_id" : ObjectId("5a314eae330cc13d0c9b10c6"), "date" : ISODate("2014-02-01T00:00:00Z") }
{ "_id" : ObjectId("5a314eae330cc13d0c9b10c7"), "date" : ISODate("2014-02-02T00:00:00Z") }
Pior to MongoDB 3.6有一种解决方法可以将您的字符串转换为词汇字符串日期:
> db.dates.aggregate([
{ "$project" : {
"date" : {
"$let" : {
"vars" : { "parts":{ "$split" : [ "$date", "/" ] } },
"in" : {
"$concat" : [
{ "$arrayElemAt" : [ "$$parts" , 2 ] },
"-",
{ "$arrayElemAt" : [ "$$parts", 1 ] },
"-",
{ "$arrayElemAt" : [ "$$parts", 0 ] } ]
}
}
}
}
},
{ "$sort" : { "date" : 1 } }
])
{ "_id" : ObjectId("5a314eae330cc13d0c9b10c4"), "date" : "2014-01-01" }
{ "_id" : ObjectId("5a314eae330cc13d0c9b10c6"), "date" : "2014-01-02" }
{ "_id" : ObjectId("5a314eae330cc13d0c9b10c5"), "date" : "2014-02-01" }
{ "_id" : ObjectId("5a314eae330cc13d0c9b10c7"), "date" : "2014-02-02" }
我知道这是用javascript而你提到它是在php中,但它实际上是相同的,检查php文档(http://php.net/manual/en/mongocollection.aggregate.php)