如何单独计算每个人的总和

Question

您好我有一张客户表，这些客户在不同时间从我们公司赚来的钱有记录是这样的：

ID     Amount Payable

1000    340.00
1001    223.00
1000    122.00
1000    344.00
1001    155.00

我当前的查询是所有表的总和，但我希望每个ID的总和不是全部。

这是我的问题：

SELECT 
     remoteemployees.RemoteEmployeeID,
         remoteemployees.Bank,
         remoteemployees.BeneficiaryName,
         remoteemployees.AccountNumber,
         SUM(transactions.AmountPayable) As TotalPayment,
         transactions.RemoteEmployeeID

         FROM remoteemployees, transactions

    WHERE
         remoteemployees.RemoteEmployeeID = transactions.RemoteEmployeeID

Answer 1

使用group by子句。请按照此link了解更多详情和教程

SELECT 
 remoteemployees.RemoteEmployeeID,
     remoteemployees.Bank,
     remoteemployees.BeneficiaryName,
     remoteemployees.AccountNumber,
     SUM(transactions.AmountPayable) As TotalPayment,
     transactions.RemoteEmployeeID

     FROM remoteemployees, transactions

WHERE 


     remoteemployees.RemoteEmployeeID = transactions.RemoteEmployeeID
     group by remoteemployees.RemoteEmployeeID

Answer 2

试试这个：

SELECT 
 remoteemployees.RemoteEmployeeID,
     remoteemployees.Bank,
     remoteemployees.BeneficiaryName,
     remoteemployees.AccountNumber,
     SUM(transactions.AmountPayable) As TotalPayment,
     transactions.RemoteEmployeeID

     FROM remoteemployees, transactions

WHERE 


     remoteemployees.RemoteEmployeeID = transactions.RemoteEmployeeID
     group by remoteemployees.RemoteEmployeeID,

Answer 3

试试这个： -

SELECT remoteemployees.RemoteEmployeeID,
       remoteemployees.Bank,
       remoteemployees.BeneficiaryName,
       remoteemployees.AccountNumber,
       SUM(transactions.AmountPayable) As TotalPayment,
       transactions.RemoteEmployeeID
FROM remoteemployees INNER JOIN transactions
ON remoteemployees.RemoteEmployeeID = transactions.RemoteEmployeeID 
GROUP BY transactions.RemoteEmployeeID;