Question

我的火车详情表，

Table Name- traindetailtb

Id  Train_Number  Train_Name       From   To
1    27658         Venad Express    ABC   XYZ
2    27659         Venad Express    XYZ   ABC

和我的火车日表，

Table Name- traindaystb
Id  Train_Number Days
1    27658       Sunday
2    27658       Wednesday
3    27659       Saturday
4    27659       Friday

这是我的列车时刻表，

Table Name- scheduletb
Id  Train_Number  Station  Time
1    27658          ABC     09:00am  
2    27658          CDE     10:00am
3    27658          XYZ     11:00am
4    27659          XYZ     12:00pm
5    27659          CDE     01:00pm
6    27659          ABC     02:00pm

将有两个输入，From和To

我需要一个查询，在给定的电台之间提供所有列车（即Train_Number，Train_Name，Days）

例如：对于输入From-CDE To-XYZ ----＆gt; 输出将是 - 27658 Venad Express S W

和输入From-XYZ To-CDE ----＆gt; 输出将是 - 27659 Venad Express M T

任何人都可以帮我这样做。

Answer 1

你在找这样的东西吗？

SELECT q.train_number, MAX(t.train_name) train_name, GROUP_CONCAT(LEFT(d.days, 1)) days
  FROM
(
  SELECT s.train_number
    FROM scheduletb s JOIN scheduletb e
      ON s.train_number = e.train_number
   WHERE s.station = 'CDE' -- from
     AND e.station = 'XYZ' -- to
     AND s.id < e.id
) q JOIN traindaystb d
    ON q.train_number = d.train_number JOIN traindetailtb t
    ON q.train_number = t.train_number
 GROUP BY q.train_number

CDE -> XYZ的输出：

| TRAIN_NUMBER |    TRAIN_NAME | DAYS |
|--------------|---------------|------|
|        27658 | Venad Express |  S,W |

XYZ -> CDE的输出：

| TRAIN_NUMBER |    TRAIN_NAME | DAYS |
|--------------|---------------|------|
|        27659 | Venad Express |  S,F |

这是 SQLFiddle 演示

Answer 2

试试这个

SELECT t.Train_Number,t.Train_Name,d.Days
from traindetailtb t,traindaystb d 
WHERE 
t.Train_Number=d.Train_Number AND From='ABC' AND To='XYZ';

然后阅读输入并将其放入from =＆＃39; ＆＃39;并且= =＆＃39; ＆＃39 ;;

这个单一查询将返回两个输出？

Answer 3

您可以尝试这样的事情： -

SELECT A.Train_number, A.Train_name, C.days
FROM traindetailtb A, traindaystb B, scheduletb C
WHERE C.Train_Number = A.Train_Number
AND A.Train_Number = B.Train_Number
AND FROM = 'ABC' AND TO = 'XYZ';

这可能会对你有帮助。

Answer 4

我建议如下：

select 
    traindetailtb.Train_Number,
    traindetailtb.Train_Name,
    traindetailtb.From,
    traindetailtb.To,
    tranddaystb.Days,
    scheduletb.Time
From 
    traindetailtb 
join trandaystb on
    traindetailtb.Train_Number=traindaystb.Train_Number 
join scheduletb on
    traindetailtb.Train_Number=scheduletb.Train_Number and
    traindetailtb.From=scheduletb.From
where 
    traindetailtb.From=$inputFrom
    and 
    traindetailtb.To=$inputTo

Answer 5

使用自联接，您可以执行此操作，假设时间实际上是时间字段

SELECT a.Train_Number, d.Train_Name, GROUP_CONCAT(e.Days)
FROM scheduletb a
INNER JOIN scheduletb b
ON a.Train_Number = b.Train_Number
AND b.Time > a.Time
INNER JOIN traindetailtb d
ON a.Train_Number = d.Train_Number
INNER JOIN traindaystb e
ON a.Train_Number = e.Train_Number
WHERE a.Station = 'CDE'
AND b.Station = 'XYZ'
GROUP BY a.Train_Number, d.Train_Name

假设您有时间的实时字段

如果您只想要从CDE直接到没有中间站的XYZ的列车，您可以在表中添加LEFT OUTER JOIN，寻找时间在另外2之间的站点： -

SELECT a.Train_Number, d.Train_Name, GROUP_CONCAT(e.Days)
FROM scheduletb a
INNER JOIN scheduletb b
ON a.Train_Number = b.Train_Number
AND b.Time > a.Time
LEFT OUTER JOIN scheduletb c
ON a.Train_Number = c.Train_Number
AND c.Time > a.Time 
AND c.Time < b.Time
INNER JOIN traindetailtb d
ON a.Train_Number = d.Train_Number
INNER JOIN traindaystb e
ON a.Train_Number = e.Train_Number
WHERE a.Station = 'CDE'
AND b.Station = 'XYZ'
AND c.Station IS NULL
GROUP BY a.Train_Number, d.Train_Name

Answer 6

如果要将单个单元格中的天数可视化而不是分散成多行，请使用GROUP_CONCAT作为聚合函数。

select tde.train_number, tde.train_name, GROUP_CONCAT(tda.days, ",") as days
from traindetailtb tde
join traindaystb tda on tda.train_number=tde.train_number
where tde.from = $user_input_from
and tde.to = $user_input_to
group by tde.train_number, tde.train_name

MySQL查询查找两个站之间的列车

6 个答案: