我使用库来解析iCalendar文件,但我不明白要拆分属性的正则表达式。
iCalendar属性有3种不同的风格:
BEGIN:VEVENT
DTSTART;VALUE=DATE:20080402
RRULE:FREQ=YEARLY;WKST=MO
库使用我想要了解的正则表达式:
var matches:Array = data.match(/(.+?)(;(.*?)=(.*?)((,(.*?)=(.*?))*?))?:(.*)$/);
p.name = matches[1];
p.value = matches[9];
p.paramString = matches[2];
感谢。
答案 0 :(得分:5)
这是一个可怕的正则表达式! .*
和.*?
意味着匹配任意数量(贪婪)或少数(懒惰)。这些只应作为最后的手段。当正则表达式与输入文本不匹配时,使用不当将导致catastrophic backtracking。所有你需要了解的这个正则表达式,你不想写这样的正则表达式。
让我说明一下我将如何处理这个问题。显然iCalendar File Format是基于行的。每行都有一个属性和一个用冒号分隔的值。该属性可以具有以分号分隔的参数。这意味着属性不能包含换行符,分号或冒号,可选参数不能包含换行符或冒号,并且该值不能包含换行符。这些知识允许我们编写一个使用negated character classes的有效正则表达式:
([^\r\n;:]+)(;[^\r\n:]+)?:(.+)
或者在ActionScript中:
var matches:Array = data.match(/([^\r\n;:]+)(;[^\r\n:]+)?:(.+)/);
p.name = matches[1];
p.value = matches[3];
p.paramString = matches[2];
正如RegexBuddy所说:
Match the regular expression below and capture its match into backreference number 1 «([^\r\n;:]+)»
Match a single character NOT present in the list below «[^\r\n;:]+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
A carriage return character «\r»
A line feed character «\n»
One of the characters “;:” «;:»
Match the regular expression below and capture its match into backreference number 2 «(;[^\r\n:]+)?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match the character “;” literally «;»
Match a single character NOT present in the list below «[^\r\n:]+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
A carriage return character «\r»
A line feed character «\n»
The character “:” «:»
Match the character “:” literally «:»
Match the regular expression below and capture its match into backreference number 3 «(.+)»
Match any single character that is not a line break character «.+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»