在SQL Server中选择不相同的记录

Question

我有一个表File_Details，有些记录是重复的。如何找到任何列中具有不同值但其余列相似的记录？

File_Details：

-----------------------
| Code  |   Name      |
-----------------------
|  123  |  text1.txt  |
|  123  |  text1.txt  |
|  124  |  text4.txt  |
|  124  |  text5.txt  |
|  125  |  text6.txt  |
|  125  |  text6.txt  |
-----------------------

我需要列出代码124，因为代码相同但Name不同

Answer 1

测试数据

DECLARE @TABLE TABLE (code INT, Name VARCHAR(100))
INSERT INTO @TABLE VALUES
(123    ,'text1.txt'),  
(123    ,'text1.txt'),  
(124    ,'text4.txt'),  
(124    ,'text5.txt'),  
(125    ,'text6.txt'),  
(125    ,'text6.txt')

查询

SELECT *
FROM @TABLE t
WHERE EXISTS (SELECT 1
              FROM @TABLE
              WHERE code = t.code
               AND  Name <> t.Name) 

结果

╔══════╦═══════════╗
║ code ║   Name    ║
╠══════╬═══════════╣
║  124 ║ text4.txt ║
║  124 ║ text5.txt ║
╚══════╩═══════════╝

Answer 2

要查找任何代码/名称组合，而不是完全重复：

SELECT Code, Name, COUNT(1) 
FROM File_Details 
GROUP BY Code, Name
HAVING COUNT(1) <> 2

Answer 3

选择包含非唯一＆＃39;代码＆＃39;但唯一＆＃39;代码＆＃39;

的记录

SELECT CODE , NAME
FROM file_Details
WHERE CODE in (SELECT CODE 
              FROM file_Details 
              GROUP BY CODE HAVING COUNT (*) > 1) 
     AND NAME IN (SELECT NAME 
                FROM file_Details 
               GROUP BY NAME HAVING COUNT (*) = 1)