我有一张桌子:
EventTime | InTeam | Points | ---------------------------------------- 2014-07-16 11:40 True 10 2014-07-16 10:00 False 20 2014-07-16 09:20 True 30 2014-07-15 11:20 False 5 2014-07-15 10:20 True 10 2014-07-15 09:00 False 10
是否可以使用以下结果进行查询:
EventDate | InTeam Points | Not In Team Point | ------------------------------------------------- 2014-07-16 40 20 2014-07-15 10 15
InTeam Points
是当天所有团队积分的总和,Not In Team Point
是当天不在团队积分中的总和?
答案 0 :(得分:5)
select date(eventtime) as eventtime,
sum(case when inteam = 'true' then points end) as in_team_points,
sum(case when inteam = 'false' then points end) as not_in_team_points
from your_table
group by date(eventtime)