SQL用户搜索查询

时间:2014-07-16 15:59:53

标签: mysql sql search

我想创建查询来搜索表users中的给定信息。表格包括:idusernamefirstnamelastnamephoneemail

示例搜索文字:mat h 50 @l d

应该返回的唯一记录:1 | admin | mat | hladeo | 123450789 | admin@localhost

我的查询:

SELECT * FROM  `users` WHERE (
(`firstname` LIKE  '%mat%') || (`firstname` LIKE  '%h%') ||
(`firstname` LIKE  '%50%') || (`firstname` LIKE  '%@l%') ||
(`firstname` LIKE  '%d%')
) && (
(`lastname` LIKE  '%mat%') || (`lastname` LIKE  '%h%') ||
(`lastname` LIKE  '%50%') || (`lastname` LIKE  '%@l%') ||
(`lastname` LIKE  '%d%')
) && (
(`phone` LIKE  '%mat%') || (`phone` LIKE  '%h%' ) ||
(`phone` LIKE  '%50%') || (`phone` LIKE  '%@l%') ||
(`phone` LIKE  '%d%')
) && (
(`email` LIKE  '%mat%') || (`email` LIKE  '%h%') ||
(`email` LIKE  '%50%' ) || (`email` LIKE  '%@l%') ||
(`email` LIKE  '%d%')
) && (
(`username` LIKE  '%mat%') || (`username` LIKE  '%h%') ||
(`username` LIKE  '%50%') || (`username` LIKE  '%@l%') ||
(`username` LIKE  '%d%')
) 

但是此查询返回的用户包含d的用户名,其电话号码包含50

修改
此查询返回3行:

1 | admin | mat | hladeo | 123450789 | admin@localhost
8 | dillese | Adriana | Zolch | 44450232 | dilesse@msn.com
12 | dcolhut | Denise | Colhut | 502222222 | dcolhut@msn.com

并且应该只返回第一行(因为匹配所有要求)。

==========

主要问题 - 如何优化此查询?是否可以简化它?

此致

1 个答案:

答案 0 :(得分:1)

我认为应该这样做:

SELECT * FROM  `users` WHERE (
       (firstname LIKE '%mat%' OR lastname LIKE '%mat%' OR
        phone LIKE '%mat%' OR email LIKE '%mat%' OR username LIKE '%mat%')
       AND
       (firstname LIKE '%h%' OR lastname LIKE '%h%' OR
        phone LIKE '%h%' OR email LIKE '%h%' OR username LIKE '%h%')
       AND
       (firstname LIKE '%50%' OR lastname LIKE '%50%' OR
        phone LIKE '%50%' OR email LIKE '%50%' OR username LIKE '%50%')
       AND
       (firstname LIKE '%@l%' OR lastname LIKE '%@l%' OR
        phone LIKE '%@l%' OR email LIKE '%@l%' OR username LIKE '%@l%')
       AND
       (firstname LIKE '%d%' OR lastname LIKE '%d%' OR
        phone LIKE '%d%' OR email LIKE '%d%' OR username LIKE '%d%')
      )

您需要单独测试每个条件,而不是每个字段。