Question

即使下面的代码工作正常，我的老板提到我应该返回一个标志（变量）而不是返回true或false。我理解那部分，但我的问题是如何在表单中获取变量的值。这是我的表格：

<form id="myForm" action="post.php" method="post" onsubmit="return validate();">

这是我的JavaScript代码

function validate(){

        if(document.getElementById('postTW').checked || document.getElementById('postFB').checked){

            var twFlag = false;
            var fbFlag = false;
            var form = document.getElementById("myForm");
            var twChecker = document.getElementsByName('twitter[]');
            var fbChecker = document.getElementsByName('fbPages[]');
            for (var i = 0; i < twChecker.length; i++) {
                if(twChecker[i].checked){
                    twFlag = true;
                }




        };
        for (var j = 0; j < fbChecker.length; j++) {
            if(fbChecker[j].checked){
                fbFlag = true;
            }
        };

        if(twFlag === false && fbFlag === false){
            alert("We can't proceed, not enough arguments");
            form.reset();
            return false;
        }
        if (fbFlag === twFlag){
            alert("tw and fb would be posted");
            return true;

        }
        else if (fbFlag === true && twFlag === false)
        {
            alert("only fb would be posted");
            return true;
        }
        else if (fbFlag === false && twFlag === true){
            alert("Only tw would be posted");
            return true;
        }

        else{
            alert("Not enough arguments ");
            form.reset();
            return false;
        }

    }


    else{
        alert("Not enough arguments to submit the form");

        return false;
    }

}

感谢您的任何建议

Answer 1

将此作为更具体的答案添加。

在表单中，添加：

<input type="hidden" name="flagged" id="flagged" value="0">

验证函数中的

：

if (fbFlag === twFlag){
            alert("tw and fb would be posted");
document.getElementById("flagged").value = 1;
            return true;

        }

现在您已将表单标记为已提交，您可以像在PHP端的任何其他POST一样检索该表单。

Answer 2

您可以像这样使用type="hidden"的输入字段

<input type="hidden" name="myfield" value="your_value">

然后在像这样的JavaScript中使用它

function validate(){
    var temp;
    //code here
    .....

        if(twFlag === false && fbFlag === false){
            alert("We can't proceed, not enough arguments");
            form.reset();
            temp = document.getElementById("myfield").value;
           // assigned value to temp variable, assign true or false as value to temp if you are returning it before form submission
            return temp; //returning temp value
        }
        if (fbFlag === twFlag){
            alert("tw and fb would be posted");
            temp = document.getElementById("myfield").value;
            // assigned value to temp variable, assign true or false as value to temp if you are returning it before form submission
            return temp; //returning temp value

        }
     .....
    }

或

你可以像这样为你的函数声明一个全局变量

var flag=false;//here I've set default value as false
function validate(){
.....
//code here and use flag variable
//for eg take this part of your code

    if(twFlag === false && fbFlag === false){
        alert("We can't proceed, not enough arguments");
        form.reset();
        flag = false;// assigning value to flag variable
        return flag; //returning flag
    }
    if (fbFlag === twFlag){
        alert("tw and fb would be posted");
        flag = true;// assigning value to flag variable
        return flag; //returning flag

    }
 .....
}

如何将变量返回到表单onsubmit事件？

2 个答案: