Question

我正在进行一个简单的用户注册这给我一些错误，我就像1小时看到其他问题和答案但没有什么可以解决我的问题，所以这里是

第一个我的register.php

<?php
if(!empty($_POST['username']) && !empty($_POST['password']))
{
$username = mysqli_real_escape_string($_POST['username']);
$password = md5(mysqli_real_escape_string($_POST['password']));
$email = mysqli_real_escape_string($_POST['email']);

 $checkusername = mysqli_query("SELECT * FROM users WHERE Username = '".$username."'");

 if(mysqli_num_rows($checkusername) == 1)
 {
    echo "<h1>Error</h1>";
    echo "<p>Sorry, that username is taken. Please go back and try again.</p>";
 }
 else
 {
    $registerquery = mysqli_query("INSERT INTO users (Username, Password, EmailAddress) VALUES('".$username."', '".$password."', '".$email."')");
    if($registerquery)
    {
        echo "<h1>Success</h1>";
        echo "<p>Your account was successfully created. Please <a href=\"index.php\">click here to login</a>.</p>";
    }
    else
    {
        echo "<h1>Error</h1>";
        echo "<p>Sorry, your registration failed. Please go back and try again.</p>";   
    }      
 }
}
else
{
?>
 <h1>Register</h1>
 <p>Please enter your details below to register.</p>

<form method="post" action="register.php" name="registerform" id="registerform">
<fieldset>
    <label for="username">Username:</label><input type="text" name="username" id="username" /><br />
    <label for="password">Password:</label><input type="password" name="password" id="password" /><br />
    <label for="email">Email Address:</label><input type="text" name="email" id="email" /><br />
    <input type="submit" name="register" id="register" value="Register" />
</fieldset>
</form>

<?php
}
?>

现在我的conexion.php

<?php
//Conexión a la base de datos
$servidor = "localhost"; //Nombre del servidor
$usuario = "myuser"; //Nombre de usuario en tu servidor
$password = "mypass"; //Contraseña del usuario
$base = "db_maquinas"; //Nombre de la BD
//conection:
$link = mysqli_connect("$servidor","$usuario","$password","$base") or die("Error " . mysqli_error($link));
?>

这是给我的错误

警告：mysqli_real_escape_string（）正好需要2个参数，1在第14行的C：\ xampp \ htdocs \ maquinas2000 \ paginas \ register.php中给出

警告：mysqli_real_escape_string（）正好需要2个参数，1在第15行的C：\ xampp \ htdocs \ maquinas2000 \ paginas \ register.php中给出

警告：mysqli_real_escape_string（）需要2个参数，第16行在C：\ xampp \ htdocs \ maquinas2000 \ paginas \ register.php中给出

警告：mysqli_query（）需要至少2个参数，1在第18行的C：\ xampp \ htdocs \ maquinas2000 \ paginas \ register.php中给出

警告：mysqli_num_rows（）要求参数1为mysqli_result，在第20行的C：\ xampp \ htdocs \ maquinas2000 \ paginas \ register.php中给出null

警告：mysqli_query（）需要至少2个参数，1在第27行的C：\ xampp \ htdocs \ maquinas2000 \ paginas \ register.php中给出

我知道是关于mysqli，但我试图弄清楚，但没有发生同样的错误..之前给了我更多的错误......我解决了一些但仍然是那些错误... THX

Answer 1

您应该简单地使用$link作为这些函数的参数：

mysqli_query($link, "your query here");

和

mysqli_real_escape_string ( $link , 'value to escape' );

用户注册php的错误

1 个答案: