“select * from users，awards where（users.id = awards.user_id）和awards.trophy_id not in（select awards.trophy_id from awards awards awards.trophy_id =＃{trophy.id}）”
答案 0 :(得分：0)
回答了自己的问题：
named_scope：not_awarded_trophy，lambda {| trophy | {：include =＆gt; ：awards，：conditions =＆gt; [“awards.trophy_id不在（选择awards.trophy_id来自奖项，其中awards.trophy_id =？）”，“trophy.id”} }