Question

将事件路由到类中的事件处理程序的最佳方法是什么，希望无需手动连接它们。

在下面的代码示例中，只需将事件强制转换为dynamic即可将事件路由到正确的处理程序。

class Program {        
    static void Main(string[] args) {
        var myEvent1 = new MyEvent1() as object;
        var myEvent2 = new MyEvent2() as object;
        var myObject = new Inherited() as Base;
        myObject.On(myEvent1);
        myObject.On(myEvent2);
    }
}

public class MyEvent1 {
}
public class MyEvent2 {
}

public class Base {
    public void On(object @event) {
        On((dynamic)@event);
    }
    public void On(MyEvent1 @event) {
        // it works!
    }
    public void On(MyEvent2 @event) {
        // it works!
    }
}

public class Inherited : Base {
}

但是，当我将类型化的事件处理程序移动到继承的类时，处理程序不再起作用了：

class Program {        
    static void Main(string[] args) {
        var myEvent1 = new MyEvent1() as object;
        var myEvent2 = new MyEvent2() as object;
        var myObject = new Inherited() as Base;
        myObject.On(myEvent1);
        myObject.On(myEvent2);
    }
}

public class MyEvent1 {
}
public class MyEvent2 {
}

public class Base {
    public void On(object @event) {
        On((dynamic)@event);
        // stack overflow happens here :(
    }
}

public class Inherited : Base {
    public void On(MyEvent1 @event) {
        // nothing happens :(
    }
    public void On(MyEvent2 @event) {
        // nothing happens :(
    }
}

显然，它需要在继承的类中使用处理程序（我必须使用myObject作为基类的实例），所以我找到了一种更好的方法来路由事件。

Answer 1

试试这个：

((dynamic)this).On((dynamic)e);

按事件对象类型路由事件

1 个答案: